Question

我在我的网站上使用PHP邮件表单。我收到的邮件很好，但我收到的标题是a7849972@srv29.000webhost.com形式，回复地址相同。如何更改我的代码以在标题中获取此人的姓名？我使用以下代码：

<?php
if(isset($_POST['submit'])) {
   $to = 'chander_info@yahoo.com' ;     //put your email address on which you want to      receive the information
   $subject = 'Message - Contact Form Coast Med Spa';   //set the subject of email.
   $headers  = 'MIME-Version: 1.0' . "\r\n";
   $headers .= 'Content-type: text/html; charset=iso-8859-1' . "\r\n";
   $mailheader = "From: ".$_POST["FirstName"]."\r\n"; 
   $mailheader .= "Reply-To: ".$_POST["email"]."\r\n";
   $message = "<table>
           <tr><td>Title</td><td>".$_POST['Title']."</td></tr>
           <tr><td>First Name</td><td>".$_POST['FirstName']."</td></tr>
           <tr><td>Last Name</td><td>".$_POST['LastName']."</td></tr>
           <tr><td>E-Mail</td><td>".$_POST['Email']."</td></tr>
           <tr><td>Phone Number</td><td>".$_POST['HomePhone']."</td></tr>
           <tr><td>Comments</td><td>".$_POST['CAT_Custom_869']."</td></tr>
           <tr><td>Contact Method</td><td>".$_POST['CAT_Custom_868']."</td></tr>
           <tr><td>Subscribe to: eNewsletter</td>     <td>".$_POST['CampaignList_41798']."</td></tr>
           </table>" ;
   mail($to, $subject, $message, $headers, $mailheader);
   header('Location: http://coastlasercenter.com/html/message-contact.html');
echo "Your message has been received";
}
?>

Answer 1

为什么要将标题分成两个不同的变量？您将From和Reply-to标题作为附加参数传递给mail()函数。检查PHP的documentation。

试试这个：

<?php
if(isset($_POST['submit'])) {
   $to = 'chander_info@yahoo.com' ;     //put your email address on which you want to      receive the information
   $subject = 'Message - Contact Form Coast Med Spa';   //set the subject of email.
   $headers  = 'MIME-Version: 1.0' . "\r\n";
   $headers .= 'Content-type: text/html; charset=iso-8859-1' . "\r\n";
   $headers .= "From: ".$_POST['FirstName']." ".$_POST['LastName']." <".$_POST['Email'].">\r\n"; 
   $headers .= "Reply-To: ".$_POST["email"]."\r\n";
   $message = "<table>
           <tr><td>Title</td><td>".$_POST['Title']."</td></tr>
           <tr><td>First Name</td><td>".$_POST['FirstName']."</td></tr>
           <tr><td>Last Name</td><td>".$_POST['LastName']."</td></tr>
           <tr><td>E-Mail</td><td>".$_POST['Email']."</td></tr>
           <tr><td>Phone Number</td><td>".$_POST['HomePhone']."</td></tr>
           <tr><td>Comments</td><td>".$_POST['CAT_Custom_869']."</td></tr>
           <tr><td>Contact Method</td><td>".$_POST['CAT_Custom_868']."</td></tr>
           <tr><td>Subscribe to: eNewsletter</td>     <td>".$_POST['CampaignList_41798']."</td></tr>
           </table>" ;
   mail($to, $subject, $message, $headers);
   header('Location: http://coastlasercenter.com/html/message-contact.html');
echo "Your message has been received";
}
?>

顺便说一下，你应该考虑验证你在$ _POST中获得的数据，然后再将它连接到你的电子邮件标题，因为它可以导致email injection attacks。

Answer 2

在代码中使用类似格式的内容：

$headers .= "From: ".$userName." <".$userEmailAddress.">";

顺便说一句，最好使用 utf-8 代替 iso-8859-1 作为你的字符集。

PHP邮件表单 - 电子邮件标题

2 个答案: