Question

function left:touch(e)
    if(e.phase == "ended") then
         boy:applyLinearImpulse(-0.1, .5, boy.x, boy.y)
    end
end

function right:touch(e)
    if(e.phase == "ended") then
        print("right"); 
        boy:applyLinearImpulse(0.1, .5, boy.x, boy.y)             
    end
end


left:addEventListener( "touch", left );
right:addEventListener( "touch" , right );

在我的游戏中，我使用applyLinearImpulse t0给倒立男人施力。当我单击左右按钮来改变x和y方向时。如何为每次触摸增加不同的力量？

Answer 1

这是你能做的将开始移动事件中的初始x，y保存为ix和iy 对于每一个移动事件，
计算ix和event.x之间的差异并应用差异dx 对y轴执行相同操作如果触摸事件结束，则为初始x，y ix和iy。

local function left:touch(event)
    if event.phase == "began" then
    --save the initial position of boy
        boy.ix,boy.iy = event.x,event.y
    elseif event.phase == "moved" then
        if boy.ix and boy.iy then
        --calculate the initial x,y with current event x,y difference
            local dx = (event.x-boy.ix)*0.4
            local dy = (event.y-boy.iy)*0.4
            boy:applyLinearImpulse(dx,dy,boy.x,boy.y)
            --boy:applyForce(dx,dy,boy.x,boy.y)
            boy.ix,boy.iy = boy.x,boy.y
        end
    elseif event.phase == "ended" or event.phase == "cancelled" then
        boy.ix,boy.iy = nil,nil
    end
end

如何在触摸功能上对电晕进行连续动作？

1 个答案: