Question

我正在尝试使用MDX查询SSAS多维数据集，我有一个在多维数据集中排序的数值列表，我想引用多维数据集中的相邻单元格以返回值。

WITH MEMBER Measures.[LastShift]<br>
AS<br>
(<br>
    [Measures].[Impact Value GBP], <br>
    [Dim Shift].[Shift Value1].PrevMember<br>
)<br>
MEMBER Measures.[NextShift]<br>
AS<br>
(<br>
    [Measures].[Impact Value GBP], <br>
    [Dim Shift].[Shift Value1].NextMember<br>
)<br>
SELECT <br>
    {NONEMPTY([Measures].[Impact Value GBP]), <br>
    Measures.LastShift,<br>
    Measures.NextShift<br>
    }<br>
    ON 0,<br>
    NONEMPTY([Dim Shift].[Shift Value1].[Shift Value1])<br>
    ON 1<br>
FROM [factTradeValues]<br>

我可以在RDBMS中看到我确实有相邻的值，但我不能让MDX返回除null之外的任何内容。也许我很厚，但看不到解决方案。

感谢您的帮助

Answer 1

PrevMember和NextMember是“成员函数”所以你需要做这样的事情......

WITH 
  MEMBER Measures.[LastShift] AS 
    (
      [Dim Shift].[Shift Value1].CurrentMember.PrevMember,
      [Measures].[Impact Value GBP]
    ) 
  MEMBER Measures.[NextShift] AS 
    (
      [Dim Shift].[Shift Value1].CurrentMember.NextMember,
      [Measures].[Impact Value GBP]
    )

Answer 2

为了回答我自己的问题，结果是prevmember和nextmember的问题，因为我想在我的标准的上下文中轮流参考下一个项目。我实际上想参考我的集合中的下一个项目，这是微妙的不同。

为了引用集合中的项目，您使用项目，然后我使用排名来获取相邻单元格。

/* Define the shifts appropriate for this scenario */
SET [SpotShifts] AS
EXCEPT(
NONEMPTY([Dim Shift].[Shift Value1].[Shift Value1].MEMBERS,
(
    [Dim Shift Entity].[Shift Entity].[GBP/FTSE],
    [Dim Date].[Date].[Date].&[20120305],
    {PriceImpacts
    }
    ,[Dim Instrument].[Arena Name].[CO/GBP/Lch10/FTSE/140908/Inc_Quarter/5L]
)),[Dim Shift].[Shift Value1].&[0])

MEMBER Measures.CurrentSpotShift
AS
StrToValue([Dim Shift].[Shift Value1].CURRENTMEMBER.NAME)

MEMBER Measures.NextSpotShift AS
IIF((Measures.CurrentSpotShift<0),
SpotShifts.Item(RANK([Dim Shift].[Shift Value1].CURRENTMEMBER,SpotShifts)-2).NAME,
SpotShifts.Item(RANK([Dim Shift].[Shift Value1].CURRENTMEMBER,SpotShifts)).NAME)

MEMBER Measures.PreviousSpotShift AS
IIF((Measures.CurrentSpotShift<0),
SpotShifts.Item(RANK([Dim Shift].[Shift Value1].CURRENTMEMBER,SpotShifts)).NAME,
SpotShifts.Item(RANK([Dim Shift].[Shift Value1].CURRENTMEMBER,SpotShifts)-2).NAME)

MEMBER Measures.NextValue AS
IIF(Measures.CurrentSpotShift>0,
([Measures].[Impact Value],SpotShifts.Item(RANK([Dim Shift].[Shift Value1].CURRENTMEMBER,SpotShifts))),
([Measures].[Impact Value],SpotShifts.Item(RANK([Dim Shift].[Shift Value1].CURRENTMEMBER,SpotShifts)-2))

SELECT      {   NONEMPTY([Measures].[Impact Value]),
            (Measures.PreviousSpotShift),
            (Measures.LastValue),
            (Measures.NextSpotShift),
            (Measures.NextValue)} ON 0,
        NONEMPTY(SpotShifts) ON 1
FROM factTradeCube

我希望这对某些人有所帮助，因为我发现在项目中使用排名并不是一个明显的解决方案，但是唯一能让我得到正确结果的人。

使用MDX延迟和引导功能

2 个答案: