Question

我需要计算日期之间的营业时间。

我需要在那几个小时后排除。

工作时间（下午6点至早上9点）
周末
假日

对于假期我有一个表HOLIDAYS

DATE        NAME
----------------------------------
2012-01-02  New Year's Day
2012-04-06  Good Friday
2012-04-09  Easter Monday

注意：
1.我有几个小时的开始和结束日期（'2012/03/15 14:00'到'2012/03/22 17:30'）。
2.我正在使用Sql Server 2005，因此我没有日期类型DATE或TIME。

Answer 1

试试这个。

DECLARE @start_date DATETIME 
DECLARE @stop_date DATETIME 
DECLARE @days INT

SELECT @start_date = '2012/03/15 14:00', @stop_date = '2012/03/22 17:30'

SELECT @days = DATEDIFF(DAY, CAST(FLOOR(CAST(@start_date AS FLOAT)) AS DATETIME), CAST(FLOOR(CAST(@stop_date AS FLOAT)) AS DATETIME)) + 1

;WITH CTE_ALL_DAYS AS (
    SELECT TOP (@days) 
        DATEADD(DAY, rn, CAST(FLOOR(CAST(@start_date AS FLOAT)) AS DATETIME)) AS dt
    FROM (
        SELECT ROW_NUMBER() OVER(ORDER BY (SELECT 1)) - 1 AS rn
        FROM master.sys.all_columns AS a
        CROSS JOIN master.sys.all_columns AS b
        ) AS tally
)
SELECT SUM(
        CASE
            WHEN dt = CAST(FLOOR(CAST(@start_date AS FLOAT)) AS DATETIME) THEN 
                CASE 
                    WHEN DATEDIFF(HOUR, @start_date, DATEADD(HOUR, 18, CAST(FLOOR(CAST(@start_date AS FLOAT)) AS DATETIME))) > 9 THEN 9
                    WHEN DATEDIFF(HOUR, @start_date, DATEADD(HOUR, 18, CAST(FLOOR(CAST(@start_date AS FLOAT)) AS DATETIME))) > 0 THEN DATEDIFF(HOUR, @start_date, DATEADD(HOUR, 18, CAST(FLOOR(CAST(@start_date AS FLOAT)) AS DATETIME))) 
                    ELSE 0 
                END
            WHEN dt = CAST(FLOOR(CAST(@stop_date AS FLOAT)) AS DATETIME) THEN 
                CASE 
                    WHEN DATEDIFF(HOUR, DATEADD(HOUR, 9, CAST(FLOOR(CAST(@stop_date AS FLOAT)) AS DATETIME)), @stop_date) > 9 THEN 9
                    WHEN DATEDIFF(HOUR, DATEADD(HOUR, 9, CAST(FLOOR(CAST(@stop_date AS FLOAT)) AS DATETIME)), @stop_date) > 0 THEN DATEDIFF(HOUR, DATEADD(HOUR, 9, CAST(FLOOR(CAST(@stop_date AS FLOAT)) AS DATETIME)), @stop_date) 
                    ELSE 0 
                END 
            ELSE 9      
        END
    )
FROM CTE_ALL_DAYS   
WHERE 
    NOT DATEPART(weekday, dt) IN (1, 7)
    AND NOT dt IN (SELECT [DATE] FROM HOLIDAYS)

在SQL中计算营业时间

1 个答案: