检索具有最大值的所有行

Question

我有这样的查询：

SELECT state AS ls,count(*) AS total, max(sales) AS ye FROM TABLE
GROUP BY state

然后我得到以下结果：

A total ye
----------
a  22   23
b  23   23
c  24   21
d  25   21

但我想只显示最大值为ye的状态，即：

A total ye
----------
a  22   23
b  23   23

Answer 1

您可以使用HAVING子句，它类似于WHERE仅在检索完所有数据后执行。您可以在分组后指定它：

select state as ls,count(*) as total ,max(sales) as ye from  table    
group by state
having count(*) = max(sales)

Answer 2

尝试：

select state as ls,count(*) as total, max(sales) as ye from  table    
group by state
having max(sales) = (select max(sales) from table)

Answer 3

select state as ls,count(*) as total ,max(sales) as ye from  table    
where sales = (select max(sales) from table)
group by state

Answer 4

尝试此查询：

select * from (select state as ls,count(*) as total ,max(sales) as ye from  table    
group by state)temp HAVING max( ye );