使用Xpath筛选记录

时间:2012-03-19 14:36:46

标签: xml xpath

我想知道是否有人可以帮助我。

我正在使用以下脚本将XML文件中的图像加载到网页中。

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml"> 
<?php 

  //This variable specifies relative path to the folder, where the gallery with uploaded files is located. 
  //Do not forget about the slash in the end of the folder name. 
  $galleryPath = 'UploadedFiles/'; 

  $thumbnailsPath = $galleryPath . 'Thumbnails/'; 

  $absGalleryPath = realpath($galleryPath) . DIRECTORY_SEPARATOR; 

  $descriptions = new DOMDocument('1.0'); 
  $descriptions->load($absGalleryPath . 'files.xml'); 
?>
<head> 
  <title>Gallery</title> 
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> 
  <link href="Libraries/fancybox/jquery.fancybox-1.3.1.css" rel="stylesheet" type="text/css" /> 
  <link href="Styles/style.css" rel="stylesheet" type="text/css" /> 
  <!--[if IE]>   
  <link href="Styles/ie.css" rel="stylesheet" type="text/css" /> 
  <![endif]-->
  <script src="Libraries/jquery/jquery-1.4.3.min.js" type="text/javascript"></script> 
  <script src="Libraries/fancybox/jquery.fancybox-1.3.1.pack.js" type="text/javascript"></script> 
  <script type="text/javascript"> 

  $(function() { $('a.fancybox').fancybox(); }); 

  </script> 
  <style type="text/css">
<!--
.style1 {
    font-size: 14px;
    margin-right: 110px;
}
.style4 {font-size: 12px}
-->
  </style>
</head>
<body style="font-family: Calibri; color:  #505050; font-size: 9px; border-bottom-width: thin; margin-top: 5px; margin-left: -475px; margin-right: 1px; margin-bottom: -10px;">
<div align="right" class="style1"> <a href = "imagefolders.php" /> View Uploaded Images In Folder Structure <a/> &larr; View All Uploaded Images </div>
  <form id="gallery" class="page"> 
  <div id="container"> 
    <div id="center"> 
      <div class="aB"> 
        <div class="aB-B"> 
          <?php if ('Uploaded files' != $current['title']) :?>
          <?php endif;?>
          <div class="demo"> 
            <div class="inner"> 
              <div class="container"> 
                <div class="gallery"> 
                  <ul class="gallery-image-list"> 
                  <?php for ($i = 0; $i < $descriptions->documentElement->childNodes->length; $i++) : 
                          $xmlFile = $descriptions->documentElement->childNodes->item($i); 
                          $name = htmlentities($xmlFile->getAttribute('originalname'), ENT_COMPAT, 'UTF-8'); 
                          $description = htmlentities($xmlFile->getAttribute('description'), ENT_COMPAT, 'UTF-8'); 
                          $folder = htmlentities($xmlFile->getAttribute('folder'), ENT_COMPAT, 'UTF-8'); 
                          $source = $galleryPath . rawurlencode($xmlFile->getAttribute('source')); 
                          $thumbnail = $thumbnailsPath . rawurlencode($xmlFile->getAttribute('thumbnail')); 
                  ?>
                    <li class="item"> 
                      <a class="fancybox" target="_blank" rel="original" href="<?php echo $source; ?>"><img class="preview" 
                        alt="<?php echo $name; ?>"  src="<?php echo $thumbnail; ?>" /></a>                      </li>
                        <li class="item"></li>
                        <p><span class="style4"><b>Image Description:</b> <?php echo htmlentities($xmlFile->getAttribute('description'));?> <br />
                            <b>Image contained in folder:</b> <?php echo htmlentities($xmlFile->getAttribute('folder'));?> </span><br />  
                          <?php endfor; ?>
                          </li>
                    </p>
                  </ul>
                </div> 
              </div> 
            </div> 
          </div> 
        </div> 
      </div> 
    </div> 
    </div> 
        <div class="aB-a">        </div> 
      </div> 
    </div> 
  </div> 
  </form> 
</body> 
</html>

使用XPath修订的代码 - NB不是工作解决方案

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml"> 
<?php 

  //This variable specifies relative path to the folder, where the gallery with uploaded files is located. 
  //Do not forget about the slash in the end of the folder name. 
  $galleryPath = 'UploadedFiles/'; 

  $thumbnailsPath = $galleryPath . 'Thumbnails/'; 

  $absGalleryPath = realpath($galleryPath) . DIRECTORY_SEPARATOR; 

  $descriptions = new DOMDocument('1.0'); 
  $descriptions->load($absGalleryPath . 'files.xml');

   $xpath = new DOMXPATH($descriptions);
?>
<head> 
  <title>Gallery</title> 
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> 
  <link href="Libraries/fancybox/jquery.fancybox-1.3.1.css" rel="stylesheet" type="text/css" /> 
  <link href="Styles/style.css" rel="stylesheet" type="text/css" /> 
  <!--[if IE]>   
  <link href="Styles/ie.css" rel="stylesheet" type="text/css" /> 
  <![endif]-->
  <script src="Libraries/jquery/jquery-1.4.3.min.js" type="text/javascript"></script> 
  <script src="Libraries/fancybox/jquery.fancybox-1.3.1.pack.js" type="text/javascript"></script> 
  <script type="text/javascript"> 

  $(function() { $('a.fancybox').fancybox(); }); 

  </script> 
  <style type="text/css">
<!--
.style1 {
    font-size: 14px;
    margin-right: 110px;
}
.style4 {font-size: 12px}
-->
  </style>
</head>
<body style="font-family: Calibri; color:  #505050; font-size: 9px; border-bottom-width: thin; margin-top: 5px; margin-left: -475px; margin-right: 1px; margin-bottom: -10px;">
<div align="right" class="style1"> <a href = "imagefolders.php" /> View Uploaded Images In Folder Structure <a/> &larr; View All Uploaded Images </div>
  <form id="gallery" class="page"> 
  <div id="container"> 
    <div id="center"> 
      <div class="aB"> 
        <div class="aB-B"> 
          <?php if ('Uploaded files' != $current['title']) :?>
          <?php endif;?>
          <div class="demo"> 
            <div class="inner"> 
              <div class="container"> 
                <div class="gallery"> 
                <ul class="gallery-image-list">  
                  <?php for ($i = 0; $i < $descriptions->documentElement->childNodes->length; $i++) : 
                          $name = $xpath->query("files/file[@userid=" . userid . " and @locationid=" . locationid . "]/@originalname");   
                          $description = $xpath->query("files/file[@userid=" . userid . " and @locationid=" . locationid . "]/@description");   
                          $folder = $xpath->query("files/file[@userid=" . userid . " and @locationid=" . locationid . "]/@folder");   
                          $source = $xpath->query("files/file[@userid=" . userid . " and @locationid=" . locationid . "]/@source");         
                          $thumbnail = $xpath->query("files/file[@userid=" . userid . " and @locationid=" . locationid . "]/@thumbnail");   
                  ?> 
                    <li class="item">  
                      <a class="fancybox" target="_blank" rel="original" href="<?php echo $source; ?>"><img class="preview"  
                        alt="<?php echo $name; ?>"  src="<?php echo $thumbnail; ?>" /></a>                      </li> 
                        <li class="item"></li> 
                        <p><span class="style4"><b>Image Description:</b> <?php echo $description;?> <br /> 
                            <b>Image contained in folder:</b> <?php echo $folder;?> </span><br />   

                          </li> 
                        </p> 
            <?php endfor; ?> 
</ul> 
                </div> 
              </div> 
            </div> 
          </div> 
        </div> 
      </div> 
    </div> 
    </div> 
        <div class="aB-a">        </div> 
      </div> 
    </div> 
  </div> 
  </form> 
</body> 
</html>

这是加载到页面中的XML文件:

  <?xml version="1.0" encoding="utf-8" ?> 
- <files>
  <file name="Test 1/_47061196_greatbritainjpg.jpg" source="_47061196_greatbritainjpg.jpg" size="227505" originalname="_47061196_greatbritainjpg.jpg" thumbnail="_47061196_greatbritainjpg.jpg" description="No description provided" userid="1" locationid="1" folder="Test_1" />  
  <file name="Test 1/article-0-07D01B74000005DC-138_468x617.jpg" source="article-0-07D01B74000005DC-138_468x617.jpg" size="143110" originalname="article-0-07D01B74000005DC-138_468x617.jpg" thumbnail="article-0-07D01B74000005DC-138_468x617.jpg" description="No description provided" userid="1" locationid="1" folder="Test_1" /> 
  <file name="Test 1/stags-snow_1544533c.jpg" source="stags-snow_1544533c.jpg" size="21341" originalname="stags-snow_1544533c.jpg" thumbnail="stags-snow_1544533c.jpg" description="No description provided" userid="1" locationid="1" folder="Test_1" /> 
  </files>

我想要做的是使图像加载用户特定,例如'locationid'值'1'的值'1'的'userid'只能查看XML文件中具有匹配值的图像

我从已阅读的教程和文章中了解到,'Xpath'语句能够做到这一点。然而,似乎有很多不同的方法可以做到这一点,并且拥有非常非常少的XML,我真的不知道从哪里开始。

我只是想知道是否有人可以给我一些帮助,请帮助我实现这一目标。

亲切的问候

1 个答案:

答案 0 :(得分:1)

没问题!

对于你的xpath语句,我假设你想要返回包含你需要的userid和locationid的xml节点的文件名。

所以你首先要从根节点开始,然后检查哪个文件有这个标准:

locationid和userid都是属性,因此在xpath中引用它们时需要使用@符号。

$xpath = new DOMXPATH($descriptions) ; 
$result = $xpath->query("files/file[@userid=" . userid . " and @locationid=" . locationid . "]/@name");

这可能看起来有点令人困惑,因为您的属性名称与输入名称相同,但“。”中的变量。是指块:

<input name="userid" type="text" id="userid" value="1" />
<input name="locationid" type="text" id="locationid" value="1" />

因此,这将为您提供该用户的文件名,您可以将其应用于$ source标记。只需重复给定的xpath并附加/ @ description或/ @ thumbnail代替name来获取其他值。

希望这有帮助,请告诉我是否需要澄清任何内容!

试试这个:

(不确定您的输入表单在原始代码中的位置,但如果您仍在使用它:)

<ul class="gallery-image-list"> 
                  <?php for ($i = 0; $i < $descriptions->documentElement->childNodes->length; $i++) :
                          $name = $xpath->query("files/file[@userid=" . userid . " and @locationid=" . locationid . "]/@originalname");  
                          $description = $xpath->query("files/file[@userid=" . userid . " and @locationid=" . locationid . "]/@description");  
                          $folder = $xpath->query("files/file[@userid=" . userid . " and @locationid=" . locationid . "]/@folder");  
                          $source = $xpath->query("files/file[@userid=" . userid . " and @locationid=" . locationid . "]/@source");        
                          $thumbnail = $xpath->query("files/file[@userid=" . userid . " and @locationid=" . locationid . "]/@thumbnail");  
                  ?>
                    <li class="item"> 
                      <a class="fancybox" target="_blank" rel="original" href="<?php echo $source; ?>"><img class="preview" 
                        alt="<?php echo $name; ?>"  src="<?php echo $thumbnail; ?>" /></a>                      </li>
                        <li class="item"></li>
                        <p><span class="style4"><b>Image Description:</b> <?php echo $description;?> <br />
                            <b>Image contained in folder:</b> <?php echo $folder;?> </span><br />  

                          </li>
                        </p>
            <?php endfor; ?>
</ul>