Question

我一直在处理一个联系表单，该表单将输出到通过电子邮件发送到地址的html电子邮件。这个过程非常有效，但它并没有将数据放在html电子邮件中供收件人阅读。

<?php
  if(isset($_POST['submit'])) {

  //create an empty errors array
  $errors = array();
  //our form has been submitted
  if($_POST['name'] == "") {
     //the name field is empty
     $errors[] = "The Name field is empty.";
  }
  if($_POST['business'] == "") {
     //the business field is empty
     $errors[] = "The Business name field is empty.";
  }
  if($_POST['telephone'] == "") {
     //the telephone number field is empty
     $errors[] = "The Telephone Number field is empty.";
  }
  if($_POST['email'] == "") {
     //the email field is empty
     $errors[] = "The Email address field is empty.";
  }
  if($_POST['enquiry'] == "") {
     //the enquiry field is empty
     $errors[] = "The Enquiry field is empty.";
  }
  if(!stripos($_POST['email'], '@')) {
      $errors[] = "The email address was not valid.";
  }
  if($_POST['antispam'] != 10) {
      $errors[] = "You entered the wrong numerical answer for the anti-spam question.";
  }
  if(count($errors) == 0) {

    // email settings
    $to  = 'email@address.com' . ', ';
    $subject = 'Website Enquiry Form';

    // headers
    $headers = 'MIME-Version: 1.0' . "\r\n";
    $headers .= 'Content-type: text/html; charset=iso-8859-1' . "\r\n";
    $headers .= 'Return-Path: email@address.com' . "\r\n";

    // form details
    $name = $_POST['name'];
    $business = $_POST['business'];
    $telephone = $_POST['telephone'];
            $email = $_POST['email'];
            $type = $_POST['type'];
            $enquiry = $_POST['enquiry'];

    $message = '
    <html>
    <head>
    <title>Website Enquiry Form</title>
    </head>
    <body>              
    The details from completed enquiry form on the website is: <br><br>   <strong> $name </strong>from <strong> $business </strong> has filled the form out. The contact details for<strong> $name </strong> is<strong> $telephone </strong> and<strong> $email </strong> is the listed email address.<br><br> <strong> $type </strong> is the selected type of enquiry.<br><br> <strong>Comments:</strong><br> $enquiry <br><br>This is the end of the enquiry form.
    </body>
    </html>
    ';

       if(mail($to, $subject, $message, $headers)) {
           $success = true;
       } else {
          $success = false;
       }
       } else {
          $success = false;
       }
    }
 ?>

这是联络查询表格的PHP。它是我之前使用的现有修改，但没有HTML输出，而“message：”中的代码曾经是：

<<<DATA
<strong>Name:</strong> $name <br>
<strong>Email:</strong> $email <br>
<strong>Why:</strong> $subject <br>
<strong>Comment:</strong> $comments<br>
DATA;

当时有效，但我尝试在HTML代码之前放置<<<DATA并以DATA;结尾，然后它就不起作用了。我不是真正的开发人员，所以我不知道从哪里开始。我希望有人可以指出我正确的方向。

Answer 1

设置$message变量时，您使用单引号（'）来分隔字符串。这导致php在中解析字符串中的变量。您可以使用双引号（“）代替：

$message = "<html><body>Name: $name</body></html>";

或者像这样连接字符串：

$message = '<html><body>Name: '.$name.'</body></html>';

Answer 2

在$ message变量上使用双引号，例如$message = "<html>...</html>"。

Answer 3

您需要在$ message中使用双引号。

联系表单以输出HTML电子邮件 - 未在电子邮件中输入数据

3 个答案: