Question

我一直在努力做到这一点，没有任何运气。由于某种原因，表单提交，但数据不会被发送到数据库。继承了PHP部分

<?php 

mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB");
if ( isset ( $_POST['Submit'] ) ) //If submit is hit
{
   $name = $_POST['name'];  
   $category = $_POST['category'];  
   $class = $_POST['class'];  
   $level = $_POST['level'];  
   $bind = $_POST['bind'];  
   $tier = $_POST['tier'];  
   $trade = $_POST['trade'];  
   $ilvl = $_POST['ilvl'];  
   $amod = $_POST['amod'];  
   $xdmg = $_POST['xdmg'];  
   $description = $_POST['description'];  
   $description2 = $_POST['description2'];  
   $description3 = $_POST['description3'];  
   $sprice = $_POST['sprice'];  
   $bprice = $_POST['bprice'];  
   $percent = $_POST['percent'];  
   $source = $_POST['source'];  
   $tnail = $_POST['tnail'];  
   $result=MYSQL_QUERY("INSERT INTO items (name, category, class, level, bind, tier, trade, ilvl, amod, xdmg, description, description2, description3, sprice, bprice, percent, source, tnail)".
   "VALUES ( '$name', '$category', '$class', '$level', '$bind', '$tier', '$trade', '$ilvl', '$amod', '$xdmg', '$description', '$description2', '$description3', '$sprice', '$bprice', '$percent', '$source', '$tnail' )")or die( "<p><span style=\"color: red;\">Unable to select table</span></p>");
   mysql_close();
   //confirm
   echo "<p><span style=\"color: red;\">Thank You; the items have been entered in the database. DO NOT REFRESH THE PAGE or data will be sent again.</span></p>"; 
}
else
{
   // close php so we can put in our code
?>

任何帮助？

Answer 1

尝试关闭你的字段名称，如（`name`，`category` ......等等。

Answer 2

在致电mysql_query()后，将以下代码放在任何地方。

echo mysql_error();

它会告诉您查询或数据库凭据是否有任何问题。

提交表单不会将数据提交到数据库

2 个答案: