Mule中非常动态的JDBC查询

时间:2012-03-26 09:55:22

标签: jdbc mule

我正在尝试在Mule中创建一个流,允许在具有动态where语句的表中进行查询。 我们的想法是发送一个包含零个或多个条目的参数映射,然后从中构建一个查询字符串。

我使用hsqldb进行测试,并获得有关意外令牌的奇怪错误。

以下是流程:

<script:transformer name="extractParameters">
  <script:script file="extractParameters.groovy" engine="groovy"/>
</script:transformer>

<flow name="datafetch.flow">
  <vm:inbound-endpoint address="vm://datafetch" exchange-pattern="request-response"/>
  <enricher target="#[variable:where-statement]">
    <transformer ref="extractParameters"/>
  </enricher>
  <jdbc:outbound-endpoint connector-ref="datasource" 
                          queryKey="parameterized-select" 
                          exchange-pattern="request-response" 
                          mimeType="text/plain">
    <jdbc:query key="parameterized-select" 
       value="select * from ${datasource.table} #[variable:where-statement]"/>
  </jdbc:outbound-endpoint>
  <json:object-to-json-transformer name="CaseInsensitiveHashMapToJson"/>
</flow>

richher是一个groovy脚本,它将json结构转换为where-statement字符串:

import groovy.json.JsonSlurper

def input = new JsonSlurper().parseText(payload)
def parameters = input?.get("parameters")
def result = ""
if(parameters==null) return result

def where = parameters.inject([]) { list, entry -> list << "${entry.key}=${entry.value}"}.join(" AND ")
if (where.isEmpty()) return result

result = "where " + where
return result

发送空参数会导致richher生成空字符串,错误为:

1. unexpected token: ? (org.hsqldb.HsqlException)
  org.hsqldb.error.Error:-1 (null)
2. unexpected token: ?(SQL Code: -5581, SQL State: + 42581) (java.sql.SQLSyntaxErrorException)
  org.hsqldb.jdbc.Util:-1 (null)
3. unexpected token: ? Query: select * from TABLE1 ? Parameters: [](SQL Code: -5581, SQL State: + 42581) (java.sql.SQLException)
  org.apache.commons.dbutils.QueryRunner:540 (null)

发送一个参数(C1 = 0)会导致更丰富的产生字符串“where C1 = 0”,错误是:

1. unexpected token: ? (org.hsqldb.HsqlException)
  org.hsqldb.error.Error:-1 (null)
2. unexpected token: ?(SQL Code: -5581, SQL State: + 42581) (java.sql.SQLSyntaxErrorException)
  org.hsqldb.jdbc.Util:-1 (null)
3. unexpected token: ? Query: select * from TABLE1 ? Parameters: [where C1=0](SQL Code: -5581, SQL State: + 42581) (java.sql.SQLException)
  org.apache.commons.dbutils.QueryRunner:540 (null)

因此,看起来查询需要的不是我写的#[variable:where-statement]

字符串

那么,我需要为where-statement变量提供什么才能使其正常工作? 或者,是否有其他方法来指定它?

1 个答案:

答案 0 :(得分:2)

我试过这种方式并且有效:

<scripting:transformer doc:name="Groovy">
        <scripting:script engine="Groovy"><![CDATA[def q ="select * from myTable where 1=1 "; 
if(payload.containsKey('param1')) q = q + " And mycolumn = " + payload.param1;

 payload.put('dynamicWhere', q);
 return payload;]]></scripting:script>
   </scripting:transformer>
 <outbound-endpoint exchange-pattern="request-response"  connector-ref="ConnectorDb" doc:name="Database" address="jdbc://#[payload.dynamicWhere]" />

...

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