Question

我想在django中进行“上下文”表单验证。考虑这种情况：

PLACE_TYPES = (
    ('RESTAURANT', 'Restaurant'),
    ('BARCLUB', 'Bar / Club'),
    ('SHOPPING', 'Shopping'),
)

RESTAURANT_FORMAT_CHOICES = (
    ('FAST_FOOD', 'Fast Food'),
    ('FAST_CASUAL', 'Fast Casual'),
    ('CASUAL', 'Casual'),
    ('CHEF_DRIVEN', 'Chef Driven'),
)

class Place(models.Model):
    place_type          = models.CharField(max_length=48, choices=PLACE_TYPES, blank=False, null=False)
    name                = models.CharField(max_length=256)
    website_1           = models.URLField(max_length=512, blank=True)
    hours               = models.CharField(max_length=1024, blank=True)

    geometry            = models.PointField(srid=4326, blank=True, null=True)

    #Restaurant Specific
    restaurant_format    = models.CharField(max_length=128, choices=RESTAURANT_FORMAT_CHOICES, blank=True, null=True)

所以在django管理员中，Place的相应表单将有下拉菜单，其中包含“餐厅，酒吧，俱乐部”等选项，还有另一个名为“restaurant_format”的字段。

如果第一个下拉列表设置为“restaurant”，则验证应确保restaurant_field不能为空。

我正在尝试这样的事情：

class PlaceAdminForm(forms.ModelForm):
    def clean(self):
        if self.cleaned_data['place_type'] == 'RESTAURANT':  
            if self.cleaned_data['place_type'] is None:
                    raise forms.ValidationError('For a restaurant you must choose a restaurant format')

但得到此错误：

异常类型：KeyError 例外价值：
place_type

异常位置：/place/admin.py in clean，第27行

Answer 1

我想我已经开始使用这个干净的例行程序了：

def clean(self):
    cleaned_data = self.cleaned_data
    place_type = cleaned_data.get("place_type")
    restaurant_format = cleaned_data.get("restaurant_format")

    if place_type == 'RESTAURANT':
        if self.cleaned_data['restaurant_format'] is None:
            raise forms.ValidationError('For a restaurant you must choose a restaurant format')

    # Always return the full collection of cleaned data.
    return cleaned_data

Django中的上下文表单验证

1 个答案: