Question

我有这些标签：

<div class="entry">entry #1</div>
<div class="subtitle">subtitle</div>
<div class="body">blah blah blah</div>
<div class="entry">entry #2</div>
<div class="subtitle">subtitle</div>
<div class="body">blah blah blah</div>
<div class="entry">entry #3</div>
<div class="subtitle">subtitle</div>
<div class="body">blah blah blah</div>
<div class="entry">entry #4</div>
<div class="subtitle">subtitle</div>
<div class="body">blah blah blah</div>

等等。如何在PHP中的每个“入口”类之间获取每个内容？使用simple_html_dom_parse还是XPath？

Answer 1

猜测这就是你想要的：

<?php
// set up to parse our input
$dom = new DOMDocument();
$dom->loadHTMLFile("./input.html");
$xpath = new DOMXPath($dom);

// initialize array to put items in and initialize an item
$list = array();
$item = array();

$divs = $xpath->query("//div");
echo "len: {$divs->length}\n";
foreach ($divs as $div) {
  $class = $div->getAttribute("class");

  // each time we see an entry, add the item we've collected
  if ($class == "entry") {
    if (count($item) > 0) $list[] = $item;
    $item = array();
  }

  // otherwise add to the item we're working on
  else {
    $item[$class] = $div->childNodes->item(0)->nodeValue;
  }
}

// pick up the last item we were working on
$list[] = $item;

// and print the result
var_dump($list);
?>

如何得到多班的兄弟姐妹

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