PHP比较两个数组并获得匹配的值而不是差异

时间:2012-04-02 00:56:56

标签: php arrays compare match

我正在尝试比较两个数组,只获取两个数组中存在的值但不幸的是,我找不到合适的数组函数...

我找到了array_diff()函数:http://php.net/manual/en/function.array-diff.php

但这是两个阵列的区别。

示例:

$array1 = array("**alpha**","omega","**bravo**","**charlie**","**delta**","**foxfrot**");
$array2 = array("**alpha**","gamma","**bravo**","x-ray","**charlie**","**delta**","halo","eagle","**foxfrot**");

预期输出:

$result = array("**alpha**","**bravo**","**charlie**","**delta**","**foxfrot**");

3 个答案:

答案 0 :(得分:80)

简单,改为使用array_intersect()

$result = array_intersect($array1, $array2);

答案 1 :(得分:2)

好的..我们需要比较动态数量的产品名称......

可能有更好的方法......但这对我有用......

...因为....字符串只是字符数组....:>}

//  Compare Strings ...  Return Matching Text and Differences with Product IDs...

//  From MySql...
$productID1 = 'abc123';
$productName1 = "EcoPlus Premio Jet 600";   

$productID2 = 'xyz789';
$productName2 = "EcoPlus Premio Jet 800";   

$ProductNames = array(
    $productID1 => $productName1,
    $productID2 => $productName2
);


function compareNames($ProductNames){   

    //  Convert NameStrings to Arrays...    
    foreach($ProductNames as $id => $product_name){
        $Package1[$id] = explode(" ",$product_name);    
    }

    // Get Matching Text...
    $Matching = call_user_func_array('array_intersect', $Package1 );
    $MatchingText = implode(" ",$Matching);

    //  Get Different Text...
    foreach($Package1 as $id => $product_name_chunks){
        $Package2 = array($product_name_chunks,$Matching);
        $diff = call_user_func_array('array_diff', $Package2 );
        $DifferentText[$id] = trim(implode(" ", $diff));
    }

    $results[$MatchingText]  = $DifferentText;              
    return $results;    
}

$Results =  compareNames($ProductNames);

print_r($Results);

// Gives us this...
[EcoPlus Premio Jet] 
        [abc123] => 600
        [xyz789] => 800

答案 2 :(得分:-1)

我认为这个问题的更好答案是

array_diff() 

因为它将数组与一个或多个其他数组进行比较,并返回数组中不存在于任何其他数组中的值。

然而

array_intersect() 返回一个数组,其中包含所有参数中出现的数组的所有值。请注意,密钥会被保留。