Symfony2:清除cookie后首次尝试登录无效

时间:2012-04-12 10:26:29

标签: authentication symfony

当尝试登录时,Symfony2告诉我,我提供了错误的凭据。第二次尝试工作。任何想法为什么会这样? 要重现这种行为,我必须注销,清除cookie,再次进入登录页面并再次登录。

我正在使用FOSUserBundle。

config.yml:

framework:
#esi:             ~
secret:          asdfsadfasdf
#translator:      { fallback: en }
charset:         UTF-8
router:          { resource: "%kernel.root_dir%/config/routing.yml" }
form:            true
csrf_protection: true
validation:      { enable_annotations: true }
templating:      { engines: ['twig'], assets_version: v1.2 } #assets_version: SomeVersionScheme
translator:      { fallback: de }

session:    
    default_locale:  de
    auto_start:     false
    lifetime:       1000000
...

security.yml:

security:
encoders:
    Symfony\Component\Security\Core\User\User: plaintext

role_hierarchy:
    ROLE_ADMIN:       ROLE_USER
    ROLE_SUPER_ADMIN: [ROLE_USER, ROLE_ADMIN, ROLE_ALLOWED_TO_SWITCH]


providers:
    fos_userbundle:
        id: fos_user.user_manager

firewalls:
    dev:
        pattern:  ^/(_(profiler|wdt)|css|images|js)/
        security: false
    login:
        pattern:  ^/login$
        security: false

    public:
        pattern:   ^/.*
        form_login:
            provider: fos_userbundle
            check_path: /login_check
            remember_me: true
        remember_me:
            key:      aaasfasdfasdfsadfsadf
            lifetime: 1296000 #15 days in second
            path:     /
        anonymous: true
        logout: true


access_control:
    - { path: ^/login, roles: IS_AUTHENTICATED_ANONYMOUSLY}
    - { path: ^/register, roles: IS_AUTHENTICATED_ANONYMOUSLY}
    #- { path: ^/_internal, roles: IS_AUTHENTICATED_ANONYMOUSLY, ip: 127.0.0.1 }
    - { path: ^/events/create, roles: ROLE_USER }
    #...
acl:
    connection: default

的routing.yml:

_imagine:
    resource: .
    type:     imagine

_index:
    resource: "@AjadoEventHubBundle/Controller/IndexController.php"
    type:     annotation

fos_comment_api:
    type: rest
    resource: "@FOSCommentBundle/Resources/config/routing.yml"
    prefix: /api

fos_user_security:
    resource: "@FOSUserBundle/Resources/config/routing/security.xml"
...

@ FOSUserBundle /资源/配置/路由/ security.xml文件:     

<routes xmlns="http://symfony.com/schema/routing"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://symfony.com/schema/routing http://symfony.com/schema/routing/routing-1.0.xsd">

    <route id="fos_user_security_login" pattern="/login">
        <default key="_controller">FOSUserBundle:Security:login</default>
    </route>

    <route id="fos_user_security_check" pattern="/login_check">
        <default key="_controller">FOSUserBundle:Security:check</default>
    </route>

    <route id="fos_user_security_logout" pattern="/logout">
        <default key="_controller">FOSUserBundle:Security:logout</default>
    </route>

</routes>

4 个答案:

答案 0 :(得分:2)

在我看来,这是您启用匿名身份验证时的预期行为:

  • 您是否申请了您的应用网址,但未被记录=&gt;使用您的会话ID
  • 创建会话cookie
  • 创建匿名令牌
  • 你清除cookie =&gt;没有更多的会话ID来识别你
  • 下一个请求,您的登录请求没有附加任何令牌......

答案 1 :(得分:1)

我不熟悉symfony,但是,当身份验证检查查找有效的cookie时,我遇到了同样的问题,但是在检查后创建了cookie - 从而导致它第二次通过,从不第一个。

答案 2 :(得分:1)

默认情况下,Symfony要求在提交表单

之前必须存在会话

来自文档

# by default, a session must exist before submitting an authentication request
# if false, then Request::hasPreviousSession is not called during authentication
# new in Symfony 2.3

为了克服这个问题,你可以设置&#34; require_previous_session&#34;在&#34; security.yml&#34;中,(默认情况下为true)为false在&#34; form_login&#34;像这样: require_previous_session:false

您可以在以下链接中阅读Symfony文档中有关它的更多信息 SecurityBundle Configuration ("security")

答案 3 :(得分:0)

我遇到了这个问题,我按照Symfony 2 “Your session has timed out or you have disabled cookies”的答案解决了这个问题。

@AlterPHP是对的,你必须登录两次,因为你第一次收到这样的错误:

Authentication request failed. (...) Your session has timed out, or you have disabled cookies.

由于您没有启动会话,因此使用此请求会创建一个新会话。下次尝试登录时,您可以登录。

您必须在require_previous_session: false文件中设置选项app/config/security.yml,以避免查找上一个会话:

security:
    firewalls:
        main:
            form_login:
                require_previous_session: false