Question

假设我有一个如下数组：

shuffleArray = [[NSMutableArray alloc] initWithObjects:@"H",@"$",@"E",@"*",@"L",@"L",@"O", nil];

我想从这个数组中只获取特殊字符

并且在获取它们之后我想从数组中删除这些特殊字符

我该怎么做？

任何帮助都会很明显。

提前完成了......

Answer 1

试试这个，

NSMutableArray *shuffleArray = [[NSMutableArray alloc] initWithObjects:@"H",@"$",@"E",@"*",@"L",@"L",@"O", nil];
    NSLog(@"Letters Array%@",[shuffleArray filteredArrayUsingPredicate:[NSPredicate predicateWithBlock:^BOOL(NSString *evaluatedString, NSDictionary *bindings) {
              return [[evaluatedString stringByTrimmingCharactersInSet:[NSCharacterSet letterCharacterSet]] length]==0;

    }]]); 
    NSLog(@"Special Characters  Array%@",[shuffleArray filteredArrayUsingPredicate:[NSPredicate predicateWithBlock:^BOOL(NSString *evaluatedString, NSDictionary *bindings) {
        return [[evaluatedString stringByTrimmingCharactersInSet:[NSCharacterSet letterCharacterSet]] length]!=0;

    }]]);

Answer 2

NSMutableArray *shuffleArray = [[NSMutableArray alloc] initWithObjects:@"H",@"$",@"E",@"*",@"L",@"L",@"O", nil];
for(int i=0; i<[shuffleArray count];i++)
{
    unichar c = [[shuffleArray objectAtIndex:i] characterAtIndex:0];
    if (![[NSCharacterSet alphanumericCharacterSet] characterIsMember:c])
    {
        NSLog(@"%c",c);
        [shuffleArray removeObjectAtIndex:i];
        i--;
    }
}

试过这个并且它有效。希望能帮助到你。快乐的编码：）

Answer 3

你使用NSPredicate：

示例：

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"memberNumber == %@", [NSNumber numberWithInt:memberNumber]];
NSArray *matchingMembers = [members filteredArrayUsingPredicate:predicate];

Customer *customer = [matchingMembers lastObject];
NSLog(@"%@", customer.name);

Here是Apple的文档链接。

Here是另一种解释

Answer 4

您需要与特殊字符匹配的正则表达式，此链接可能会对您有所帮助。

你的正则表达式是这样的“[^ [A-Za-z] [0-9]]”

How to get matches in iOS using regular expression?

iPhone：如何从数组中获取特殊字符

4 个答案: