Question

我正在尝试显示AnnualBudget中的最小值，这是我到目前为止所做的代码：

SELECT WARD.HospitalCode,
       HOSPITAL.HospitalCode Name,
       WardNo,
       AnnualBudget
FROM WARD,
     HOSPITAL
WHERE (AnnualBudget) =
    (SELECT AnnualBudget
     FROM WARD
     WHERE AnnualBudget =
         (SELECT MIN(AnnualBudget)
          FROM WARD
          WHERE AnnualBudget >
              (SELECT MIN(AnnualBudget)
               FROM WARD
          ) 
     )
);

然而，不是选择最小值而是实际选择最大值，有人可以帮忙吗？

Answer 1

以下查询将为您提供高于min

的内容

select min(annualbudget)
from ward
where annualbudget > (
  select min(annualbudget)
  from ward
)

如果你想要分钟，试试这个：这些天我没有太多的oracle，但它应该有效）

select (stuff)

from ward w
join hospital h on h.hospitalId = w.hostpitalId

where w.annualbudget = (select min(annualbudget) from ward)

Answer 2

这不应该更像这样吗？

SELECT W.HospitalCode, H.HospitalCode, Name, WardNo, AnnualBudget  
FROM WARD W, HOSPITAL H 
WHERE W.HospitalCode = H.HospitalCode
  and W.AnnualBudget = (Select MIN(AnnualBudget) FROM WARD W2 
                                                WHERE W2.HospitalCode = W.HospitalCode)

我认为WARD中的医院代码是外键，你希望每家医院的病房预算最低，对吗？

试图找到最小值

2 个答案: