Question

每当鼠标离开按钮时，我想让menubar.handmove可见。但是，当我查看/单击按钮时，可见性将为false，但是当我将鼠标移到按钮时，它将不会返回true。

我该怎么办？

stop();

menubar.play_but.addEventListener(MouseEvent.CLICK, playgame);
menubar.intr_but.addEventListener(MouseEvent.MOUSE_OVER, overdown1);
menubar.play_but.addEventListener(MouseEvent.MOUSE_OVER, overdown);
menubar.intr_but.addEventListener(MouseEvent.CLICK, instruc);
stage.addEventListener(MouseEvent.MOUSE_MOVE, menu);

var mouseE:Boolean = false;

function playgame(e:MouseEvent):void {
gotoAndPlay(63);
mouseE=true;
}

function overdown(e:MouseEvent):void {
 mouseE=true;
}

function instruc(e:MouseEvent):void {
gotoAndPlay(64);
mouseE=true;
}

function overdown1(e:MouseEvent):void {
mouseE=true;
}

function menu(e:MouseEvent):void {

if(mouseE==false;){
menubar.handmove.visible=true;
}else{
menubar.handmove.visible=false;
}
}

Answer 1

您应该将此代码添加到现有代码中：

menubar.intr_but.addEventListener(MouseEvent.MOUSE_OUT, moveout);
menubar.play_but.addEventListener(MouseEvent.MOUSE_OUT, moveout);

function moveout(e:MouseEvent):void {
    mouseE=false;
}

同时删除字符;以便成功编译。必须是：

if(mouseE==false){

Flash CS3鼠标事件

1 个答案: