Question

我有以下代码，用于计算每月发送的邮件数。这可以改为每日吗？我尝试了一些改动，但他们没有成功。有什么建议？非常感谢你提前！我是PHP / MySQL的新手。另外，我知道当前的MySQL查询已被弃用！：

$vmYear = date("Y"); 
$vmMonth = date("m"); 

$vmfromdate = mktime(0,0,0,$vmMonth,"1",$vmYear); 
$vmtodate = mktime(0,0,0,$vmMonth,"31",$vmYear); 

$verifmessagespermonth = mysql_query("SELECT ID FROM messages WHERE msg_from = '$session_memberid' AND ( time BETWEEN '$vmfromdate' AND '$vmtodate' )"); 
$nummessagesthismonth = mysql_num_rows($verifmessagespermonth); 
} else { 
$nummessagesthismonth = 0; 
}

Answer 1

通过添加日期（假设您只存储日期），将int保留在与您相同的结构中。如果您存储日期+时间，则可能需要将0,0,0从$vmtodate更改为23,59,59

$vmYear = date("Y"); 
$vmMonth = date("m");
$vmDay = date("d");

$vmfromdate = mktime(0,0,0,$vmMonth,$vmDay,$vmYear); 
$vmtodate = mktime(0,0,0,$vmMonth,$vmDay,$vmYear);

如果你愿意，这仍然允许你制作其他范围

Answer 2

如果我正确理解了您可以使用此查询的要求：

SELECT 
  ID 
FROM 
  messages 
WHERE 
  msg_from = '$session_memberid' 
  AND time BETWEEN 
     DATE_FORMAT(NOW() , '%Y-%m-%d 00:00:00' ) 
     AND DATE_FORMAT(NOW() , '%Y-%m-%d 23:59:59' )

将此更改从每月重置到每天？

2 个答案: