Question

我的问题是我不能让内部捕获抛出异常。在这里，我希望将ex扔到外部捕获。

Runnable(){

public void run(){
try{
    try{
       }catch(Exception ex){
        System.out.println("Inner");
        throw ex; //I get an error here
    }
}catch(Exception e){
    System.out.println("Outer");
}}

错误消息：必须捕获未报告的异常，声明为抛出

Answer 1

将块放入函数中.....

private void myFunction() throws Exception {

    try{
       }catch(Exception ex){
        System.out.println("Inner");
        throw ex; //I get an error here
    }
}

然后从代码块中调用它

Runnable(){

public void run(){
    try{
        myFunction();
    }catch(Exception e){
    System.out.println("Outer");
}}

Answer 2

这似乎功能正常。制作嵌套的try-catch块被认为是不好的做法。

public class Test implements Runnable {

public void run() {
    try {
        try {
            throw new IOException("bad"); //throw something here
        } catch (Exception ex) {
            System.out.println("Inner");
            throw ex; 
        } finally  {

        }
    } catch (Exception e) {
        System.out.println("Outer");
    }
}


public static void main(String[] args) {
    new Test().run();
}

}

// PRINTS: 
// Inner
// Outer

Answer 3

试试这个。

Callable(){

public void call(){
try{
try{
   }catch(Exception ex){
    System.out.println("Inner");
    throw ex; //I get an error here
}
}catch(Exception e){
System.out.println("Outer");
}}

扔进线程中的Catch

3 个答案: