Question

对不起，我是新手。继续我的函数原型和调用问题。我认为我的函数调用或原型是不正确的。我只想将box.item和box.bin的值传递给Stackers。实际上我想在这里做的是两个有两个Stack，一个是Stacker和Truck。两者都使用Stack，void truck(){}使用动态内存分配。并且void stacker(){}固定大小为5.我已根据我想要的内容绘制图像：

enter image description here

#include <stdlib.h>
#include <stdio.h>



    struct box
    {
        int item;
        int bin;
        int top;
    }*boxs,stacker[5];

     void stackers(struct box *);

    int i;
    int num,a;
    int topt = -1;
    int tops = -1;


     void truck();
     void display();
void display()
{
    for(i=0;i<=topt;i++)
    {
        printf("\n%d",boxs[i].item);
        printf("\n%d",boxs[i].bin);
        printf("\nstacker%d",stacker[i].item);
        printf("\nstacker%d",stacker[i].bin);
    }
}
    void main()
    {

        int op;//option
        char ch;//choice 

        do{
            system("cls");
            printf("\n Stack:-");
            printf("\n\n 1.<Insert>");
            printf("\n 2.<Display>");
            printf("\n\n Option: ");

            scanf("%d", &op);fflush(stdin);

            switch(op)
                 {
                     case 1:truck();break;
                     case 2:display();break;
                     default:printf("\n Invalid Choice!!!");break;

                 } printf("\n\n\n Continue?(Y/N): ");

                 scanf("%c", &ch);    fflush(stdin);
            }while(ch=='y' || ch=='Y');
        return;
    }


    void truck()
    {
        struct box e;
        int temp;

        printf("Enter Number of Boxes to unload from the Truck: ");
        scanf("%d", &num);
        boxs= (struct box*)malloc(num*sizeof (struct box));
        temp=num;
        /*tempt->tops=copy-1;*/

        for(a=0; a<num;a++)
        {
        topt++;
        temp--;
        /*tempt[copy-a].tops--;*/
        printf("\n1. Enter Item ID: ");
        scanf("%d", &e.item);
        boxs[a].item=e.item;fflush(stdin);
        /*tempt[copy-a].item=e.item;*/


        printf("\n2. Enter Bin ID: ");
        scanf("%d", &e.bin);
        boxs[a].bin=e.bin;fflush(stdin);
        //tempt[copy-a].bin=e.bin;
       stackers(boxs); 
        }

    }



void stackers(struct box * pass)
{
    if(tops==4)
    {

    }
    else{
        tops++;
        stacker[tops].item=pass->item;
        stacker[tops].bin=pass->bin;
    }
}

Answer 1

更改

void stackers(struct box boxs);
... 
stackers(&boxs); // call

到

void stackers(struct box *);
... 
stackers(boxs); // call

已更新：对于新的更新代码，仍有几个问题：

您没有包含所需的标题：
```
#include <stdlib.h>
#include <stdio.h>
```
将函数声明放在main()之前，而不是放在其中：
```
void truck();
void display();
void main()
{
```
您没有定义函数display()。

Answer 2

有两种方法可以做到这一点。

堆栈：

struct box mybox;
stackers(&mybox); // call by address on the stack

堆：

struct box * mybox_pointer = calloc(sizeof(struct box), 1);
stackers(mybox_pointer); // call by pointer

Answer 3

这是另一种方式......

注意： 使用typedef。这允许您使用typedef'd name 创建结构实例

阅读（希望有用的）解释的内联评论......

#include <stdio.h>
#include <stdlib.h>
typedef struct 
{
    int item;
    int bin;
    int top;
}BOX; //BOX is now a type, and can be used to create instances of your struct.

BOX stacker[5], *boxs;//create array of 5, and pointer to an instance of the struct.

void stackers(BOX *a);//prototype of your function

       //stackers(&boxs); // call (you cannot call a function outside of a block, {...})
int main(void)//must include a main function (for any C program)
{             //program starts when operating system calls this function
    boxs = &stacker[0]; //initialize pointer to BOX like this
    stackers(boxs); // call it here (note, no & needed)
    return 0;
}

void stackers(BOX *pass)
{
    if(pass[0].top==4)
    {

    }
    else{//not sure what you are doing here, changes simply reflect what needed to be done for a compile build
        pass[0].top++;
        stacker[pass[0].top].item=pass[0].item;
        stacker[pass[0].top].bin=pass[0].bin;
    }
}

将Struct指针传递给函数

3 个答案: