我正在努力将列表字典写入.csv文件。
这就是我的字典的样子:
dict[key1]=[1,2,3]
dict[key2]=[4,5,6]
dict[key3]=[7,8,9]
我希望.csv文件看起来像:
key1 key2 key3
1 4 7
2 5 8
3 6 9
首先我写下标题:
outputfile = open (file.csv,'wb')
writefile = csv.writer (outputfile)
writefile.writerow(dict.keys())
到目前为止一直这么好......但是,我的问题是我不知道如何将一个列表分配给相应的列。 e.g:
for i in range(0,len(dict[key1])):
writefile.writerow([dict[key1][i],dict[key2][i],dict[key3][i])
将随机填充列。另一个问题是,我必须手动填写密钥,不能将它用于另一个带4个密钥的字典。
答案 0 :(得分:28)
如果您不关心列的顺序(因为字典是无序的),您只需使用zip()
:
d = {"key1": [1,2,3], "key2": [4,5,6], "key3": [7,8,9]}
with open("test.csv", "wb") as outfile:
writer = csv.writer(outfile)
writer.writerow(d.keys())
writer.writerows(zip(*d.values()))
结果:
key3 key2 key1
7 4 1
8 5 2
9 6 3
如果您关心订单,则需要对键进行排序:
keys = sorted(d.keys())
with open("test.csv", "wb") as outfile:
writer = csv.writer(outfile, delimiter = "\t")
writer.writerow(keys)
writer.writerows(zip(*[d[key] for key in keys]))
结果:
key1 key2 key3
1 4 7
2 5 8
3 6 9
答案 1 :(得分:1)
鉴于
dict = {}
dict['key1']=[1,2,3]
dict['key2']=[4,5,6]
dict['key3']=[7,8,9]
以下代码:
COL_WIDTH = 6
FMT = "%%-%ds" % COL_WIDTH
keys = sorted(dict.keys())
with open('out.csv', 'w') as csv:
# Write keys
csv.write(''.join([FMT % k for k in keys]) + '\n')
# Assume all values of dict are equal
for i in range(len(dict[keys[0]])):
csv.write(''.join([FMT % dict[k][i] for k in keys]) + '\n')
生成一个类似于:
的csvkey1 key2 key3
1 4 7
2 5 8
3 6 9
答案 2 :(得分:1)
在没有csv模块的情况下滚动自己:
d = {'key1' : [1,2,3],
'key2' : [4,5,6],
'key3' : [7,8,9]}
column_sequence = sorted(d.keys())
width = 6
fmt = '{{:<{}}}'.format(width)
fmt = fmt*len(column_sequence) + '\n'
output_rows = zip(*[d[key] for key in column_sequence])
with open('out.txt', 'wb') as f:
f.write(fmt.format(*column_sequence))
for row in output_rows:
f.write(fmt.format(*row))
答案 3 :(得分:0)
key_list = my_dict.keys()
limit = len(my_dict[key_list[0]])
for index in range(limit):
writefile.writerow([my_dict[x][index] for x in key_list])
答案 4 :(得分:0)
with open(path, 'a') as csv_file:
writer = csv.writer(csv_file)
for key, value in dict_.items():
writer.writerow([key, ','.join(value)])
csv_file.close()
print ('saving is complete')
with open(csv_path, 'rb') as csv_file:
reader = csv.reader(csv_file);
temp_dict = dict(reader);
mydict={k:v.split(',') for k,v in temp_dict.items()}
csv_file.close()
return mydict
答案 5 :(得分:0)
即使键中的列表长度不同,这也将起作用。
with myFile:
writer = csv.DictWriter(myFile, fieldnames=list(clusterWordMap.keys()))
writer.writeheader()
while True:
data={}
for key in clusterWordMap:
try:
data[key] = clusterWordMap[key][ind]
except:
pass
if not data:
break
writer.writerow(data)