Question

我试图让我的第二个规格失败，但它不会失败。我从我的服务器返回statusCode 203，测试将其作为203接收，但由于某种原因，expect块仍然不会引发错误。这是怎么回事？

spec.js

var chai = require('chai');
var expect = chai.expect;
var request = require('request');
var localServerUri = 'http://127.0.0.1:3000/';

describe('server http routing', function(done){
  it('should receive a status code 200 after GET request', function() {
    request(localServerUri + 'pull', function (error, response, body) {
      expect(response.statusCode).to.be.at(200);
      done();
    });
  });

  it('should receive a status code 201 after POST request', function() {
    request.post({url:localServerUri + 'push', form: {key:'value'}}, function(err, response, body) { 
      //why wont this fail?
      console.log(response.statusCode === 201);
      expect(response.statusCode === 201).to.be.true;
      done();
    });
  });
});

app.js var express = require（＆＃39; express＆＃39;）; var app = express（）;

app.get('/pull', function (req, res) {
  res.send('works');
});

app.post('/push', function(req, res) {
  res.status(203);
  res.send('works');
});

var server = app.listen(3000, function () {

  var host = server.address().address;
  var port = server.address().port;

  console.log('Example app listening at port', host, port);

});

Answer 1

您需要将done传递到it块，而不是describe。

var chai = require('chai');
var expect = chai.expect;
var request = require('request');
var localServerUri = 'http://127.0.0.1:3000/';

describe('server http routing', function(){
  it('should receive a status code 200 after GET request', function(done) {
    request(localServerUri + 'pull', function (error, response, body) {
      expect(response.statusCode).to.be.at(200);
      done();
    });
  });

  it('should receive a status code 201 after POST request', function(done) {
    request.post({url:localServerUri + 'push', form: {key:'value'}}, function(err, response, body) { 
      expect(true).to.be.true;
      done();
    });
  });
});

Answer 2

这很简单。您传递给it两个来电的回调应该是function (done) {...而不是function () {...。现在，Mocha认为这些测试是同步的，所以它不会等待它们完成。

您传递给describe的回调需要done参数，但这没用。

ChaiJS：不能导致测试失败

2 个答案: