我在WebView中加载网页。网页上有一个链接，在桌面上会下载该文件，但在应用程序中，该链接应显示Toast，表示该应用程序已禁用该链接。
点击链接时，我不确定如何从锚标记的href获取值。
<a class="btn btn-primary" download="http://xx.xxx.com/wp-content/uploads/2015/11/abc-27-15.mp3" href="http://xx.xxx.com/wp-content/uploads/2015/11/abc-27-15.mp3">
<i class="fa fa-download"></i> Download Audio</a>
有人可以分享有关如何执行此操作的想法或任何示例代码。
编辑：1
这是我目前正在做的事情：
private static final String URL = "http://xx.xxx.com/wp-content/uploads/";
webView.setOnTouchListener(new View.OnTouchListener() {
@Override
public boolean onTouch(View v, MotionEvent event) {
if (event.getAction() == MotionEvent.ACTION_DOWN) {
WebView.HitTestResult hr = ((WebView) v).getHitTestResult();
String extra = hr.getExtra();
if (extra != null && extra.startsWith(URL) && extra.endsWith(".mp3")) {
Log.d("WebviewActivity", "Extra: " + extra);
Log.d("WebviewActivity", "Contains URL");
return true;
}
}
return false;
}
});
这种方法的问题是： 当我点击链接时，我得到额外的网址。它工作正常，直到这里。但是，从下一次开始，无论我在哪里点击webview，都会返回相同的额外内容。因此，即使我点击了网址后点击图片，我也会获得相同的网址。不确定我做错了什么。或者这是正确的方法。
如果您需要任何细节，请与我们联系。
编辑：2
private Handler mHandler = new Handler() {
@Override
public void handleMessage(Message msg) {
// Get link-URL.
String url = (String) msg.getData().get("url");
// Do something with it.
if (url != null) {
Log.d(TAG, "URL: "+url);
}
}
};
webView.setOnTouchListener(new View.OnTouchListener() {
@Override
public boolean onTouch(View v, MotionEvent event) {
if (event.getAction() == MotionEvent.ACTION_DOWN) {
WebView.HitTestResult hr = ((WebView) v).getHitTestResult();
if (hr.getType() == WebView.HitTestResult.SRC_ANCHOR_TYPE) {
Message msg = mHandler.obtainMessage();
webView.requestFocusNodeHref(msg);
}
}
return false;
}
});
webView.loadUrl(mUrl);
}
现在，我获取在上一个action_down事件中单击的URL。如何获取当前的URL？
编辑3（尝试使用webviewclient：
private class MyWebViewClient extends WebViewClient {
private static final String URL = "xx.xxx.com/wp-content/uploads/";
@Override
public void onPageStarted(WebView view, String url, Bitmap favicon) {
super.onPageStarted(view, url, favicon);
if (!isFinishing())
mProgressDialog.show();
}
@Override
public void onPageFinished(WebView view, String url) {
super.onPageFinished(view, url);
mProgressDialog.dismiss();
}
@Override
public void onReceivedError(WebView view, int errorCode,
String description, String failingUrl) {
super.onReceivedError(view, errorCode, description, failingUrl);
Toast.makeText(WebviewActivity.this,
"Please check your internet " + "connection and try again",
Toast.LENGTH_SHORT).show();
}
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
Log.d("xxx", "Url: " + url);
if(url.contains(URL)) {
Log.d("xxx", "Url Contains: " + URL);
return true;
}
return false;
}
}
mMyWebViewClient = new MyWebViewClient();
webView.setWebViewClient(mMyWebViewClient);
单击链接时在logcat中输出：
03-01 15:38:19.402 19626-19626/com.xx.xxx D/cr_Ime: [ImeAdapter.java:553] focusedNodeChanged: isEditable [false]
03-01 15:38:19.428 19626-19626/com.xx.xxx D/cr_Ime: [ImeAdapter.java:253] updateKeyboardVisibility: type [0->0], flags [0], show [true],
03-01 15:38:19.428 19626-19626/com.xx.xxx D/cr_Ime: [ImeAdapter.java:326] hideKeyboard
03-01 15:38:19.429 19626-19626/com.xx.xxx D/cr_Ime: [InputMethodManagerWrapper.java:56] isActive: true
03-01 15:38:19.429 19626-19626/com.xx.xxx D/cr_Ime: [InputMethodManagerWrapper.java:65] hideSoftInputFromWindow
答案 0 :(得分：4)
因为您使用的是WebView且链接不是Java脚本，所以使用可用于监视WebView的WebViewClient非常容易实现
myWebView.setWebViewClient( new WebViewClient() {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
// check something unique to the urls you want to block
if (url.contains("xx.xxx.com")) {
Toast.make... //trigger the toast
return true; //with return true, the webview wont try rendering the url
}
return false; //let other links work normally
}
} );
可能因为您的网址以.mp3结尾，该文件被视为资源。您还应该覆盖WebViewClient的shouldInterceptRequest方法来检查它。
@Override
@TargetApi(Build.VERSION_CODES.LOLLIPOP)
public WebResourceResponse shouldInterceptRequest(WebView view, WebResourceRequest request) {
String url = request.getUrl().toString();
Log.d("XXX", "Url from API21 shouldInterceptRequest : " + url);
if (url.contains(URL)) {
return new WebResourceResponse("text/html", "UTF-8", "<html><body>No downloading from app</body></html>");
} else {
return null;
}
}
public WebResourceResponse shouldInterceptRequest (WebView view, String url) {
Log.d("XXX", "Url from shouldInterceptRequest : " + url);
if (url.contains(URL)) {
return new WebResourceResponse("text/html", "UTF-8", "<html><body>No downloading from app</body></html>");
} else {
return null;
}
}
答案 1 :(得分：0)
大部分工作都可以在网页侧完成。你必须编写java脚本来识别哪个设备正在访问该页面（移动设备，桌面等），如果它的移动设备然后使用java脚本绑定技术调用本机android代码来显示Toast消息。
http://developer.android.com/guide/webapps/webview.html
WebView webView = (WebView) findViewById(R.id.webview);
webView.addJavascriptInterface(new WebAppInterface(this), "Android");
WebAppInterface.java
public class WebAppInterface {
Context mContext;
/** Instantiate the interface and set the context */
WebAppInterface(Context c) {
mContext = c;
}
/** Show a toast from the web page */
@JavascriptInterface
public void showToast(String toast) {
Toast.makeText(mContext, toast, Toast.LENGTH_SHORT).show();
}
}
YourHTML页面（此示例点击了一下按钮）
<input type="button" value="Say hello" onClick="showAndroidToast('Hello
Android!')" />
<script type="text/javascript">
function showAndroidToast(toast) {
Android.showToast(toast);
}
</script>