Question

我的程序应该使用DFS函数来搜索XML树并打印输入的那个事件的子节点。到目前为止我遇到的问题是尝试将元素树解析为我的dfs函数将采用的格式。

我的代码：

import xml.etree.ElementTree as ET
tree = ET.ElementTree(file='XMLStuff3.xml')


root = tree.getroot()









def dfs(adjLists, s):
    stack = [s]
    visited = set()

    while stack:
        v = stack.pop()
        if v in visited:
            continue
        print(v, " ", end='')

        visited.add(v)
        yield v
        for w in adjLists.get(v, []):
            stack.append(w)

# ------------------------------------------------------------------



from xml.etree import ElementTree

with open('XMLStuff3.xml') as f:
    tree = ElementTree.parse(f)

for node in tree.iter():

    print(node.attrib)



l1 =[]
while True:
    event = input("Enter Event (or Enter to quit): ")
    if not event:
        break
    for child in  root:
        l1 = [ child.attrib['action'] for child in root ]
        if any(event in e for e in l1):
            dfs(node.attrib, event) #Event is supposed to go into dfs as the root node where the function returns the childs of that node


            print("Match", )

        else:
            print('No Match')


print("Done")

我正在使用的XML文件：

<?xml version="1.0"?>
<root>
    <node action="Stay" response="">
        <node action="" response="Pause Menu"/>
        <node action="" response="Sit"/>
    </node>
    <node action="Enemy Rushing User" response="">
        <node action="" response="Dodge Left"/>
        <node action="" response="Dodge Right"/>
    </node>
    <node action="Move" response="">
        <node action="Reverse" response="">
            <node action="" response="Back Left"/>
            <node action="" response="Back Straight"/>
            <node action="" response="Back Middle"/>
        </node>
        <node action="Forward" response="">
            <node action="" response="Forward Left"/>
            <node action="" response="Forward Straight"/>
            <node action="" response="Forward Right"/>
        </node>
    </node>
</root>

到目前为止，当我输入类似'Stay'的事件时，它会找到一个匹配项，但下一行的dfs函数不会执行，因为它的格式不正确。函数将采用的格式是我自己尝试和工作的：

adjLists1 = {'0':['One','Two','Three'], '1':['Four'], '2':['Five','Six'], '3':['Seven','Eight'], '4':[],
             '5':['Nine','Ten','Eleven'], '6':['Twelve','Thirteen','Fourteen'], '7':[], '8':[]

我的一般问题是如何将xml树解析为该格式？我试过在dfs函数中使用'node.attrib'作为'adjLists'参数，它接近那个格式但还不够。

使用dfs搜索元素树

0 个答案: