绘制网格，按照鼠标

Question

我需要在白色方块的交互窗口上创建一个10 * 10网格。然后我需要在中间画一个正方形，并让正方形跟随鼠标。一旦方块通过网格上的方框，更改该方框的颜色，然后根据该颜色移动方块：

○白色：方块向鼠标移动

○蓝色：方形远离鼠标

○绿色：方块随机移动

○红色：方格根本不移动

我的问题是，如何分配网格以便它知道方块何时通过其中一个索引？

public static void main(String[] args)
 {
  StdDraw.setScale(0, 100);

  int[][] grid = new int[10][10];
  int gridState = 0;
  int antCoord = 0; 
  int mouseCoord = 0;

  moveAnt(gridState, antCoord, mouseCoord);

  while (true)
   {
     for (int i = 0; i <= 100; i++)
      {
        StdDraw.filledSquare(StdDraw.mouseX(), StdDraw.mouseY(), 1);
      }
   }
  } // end of main

   public static int moveAnt(int gridState, int antCoord, int mouseCoord)
   {
     double mouseMoveX = StdDraw.mouseX();
     double mouseMoveY = StdDraw.mouseY();
     if (StdDraw.mousePressed())
     {
       StdDraw.setPenColor(StdDraw.RED);
       StdDraw.filledSquare(StdDraw.mouseX(), StdDraw.mouseY(),  1);
      }

     if (mouseMoveX == mouseMoveX+1)
      {
        StdDraw.setPenColor(StdDraw.BLUE);
        StdDraw.filledSquare(StdDraw.mouseX(), StdDraw.mouseY(), 1);
       }
     return antCoord;
     } // end of moveAnt