麻烦将scrapy导入json

时间:2016-04-21 02:38:45

标签: web-scraping scrapy scrapy-spider

我正在尝试从Craigslist中提取一些信息并将其存储在JSON文件中,但信息存储有点错误。而不是拥有[标题,链接,位置,时间]的数组,我得到一个包含所有标题的数组,一个包含所有链接,等等。我的标题是错误的还是for循环本身错了?

from scrapy.spiders import BaseSpider
from scrapy.selector import HtmlXPathSelector
from scrapy.selector import Selector
from craigslist_sample.items import CraigslistSampleItem

class MySpider(BaseSpider):
 name = "craig"
 allowed_domains = ["craigslist.org"]
 start_urls = ["https://pittsburgh.craigslist.org/search/ccc"]

 def parse(self, response):
    titles = response.selector.xpath("//p[@class='row']")
    items = []
    for titles in titles:
        item = CraigslistSampleItem()
        item["title"] = titles.xpath("//span[@id='titletextonly']").extract()
        item["link"] = titles.xpath("a/@href").extract()
        item["location"] = titles.xpath("//small").extract()
        item["time"] = titles.xpath('//time').extract()
        items.append(item)
    return items

1 个答案:

答案 0 :(得分:1)

那是因为你的内部xpaths匹配从树根开始的元素。相反,您需要通过添加一个点来强制它们在每个项目的上下文中工作:

for title in titles:
    item = CraigslistSampleItem()
    item["title"] = title.xpath(".//span[@id='titletextonly']").extract()
    item["link"] = title.xpath("a/@href").extract()
    item["location"] = title.xpath(".//small").extract()
    item["time"] = title.xpath('.//time').extract()
    yield item