Question

我有一个表batch_detail_process有外键batch_detail_id，它在模型中与belongsTo连接。现在我希望在article_id＆amp;的基础上获得ArticleRatio。 ITEM_ID。

我的表外键如下：

batch_details_processes = id，batch_detail_id

batch_details = id，batch_id，item_id

batch = id，article_id，

article_ratios = id，article_id，item_id，ratio

$conditions = array();

$conditions['joins'] = array(
                array(
                    'table' => 'batches',
                    'alias' => 'Batch',
                    'type' => 'LEFT',
                    'conditions' => array(
                        'Batch.id = BatchDetail.batch_id'
                    )
                ),
                array(
                    'table' => 'article_ratios',
                    'alias' => 'ArticleRatio',
                    'type' => 'LEFT',
                    'conditions' => array(
                        'ArticleRatio.article_id = Batch.article_id',
                        'ArticleRatio.item_id = BatchDetail.item_id'
                    )
                )
            );

        $bdp = $this->BatchDetailsProcess->find('all',$conditions);

pr($bdp);

返回以下内容：

由它生成的SQL：

SELECT  `BatchDetailsProcess`.`id`, `BatchDetailsProcess`.`batch_detail_id`,
        `BatchDetailsProcess`.`qty_in`, `BatchDetailsProcess`.`qty_out`,
        `BatchDetailsProcess`.`process_step_id`, `BatchDetailsProcess`.`qc_test`,
        `BatchDetailsProcess`.`qc_note`, `BatchDetailsProcess`.`qc_accept`,
        `BatchDetailsProcess`.`qc_reject`, `BatchDetailsProcess`.`moved_further`,
        `BatchDetailsProcess`.`assigned_to`, `BatchDetailsProcess`.`receive_confirmation`,
        `BatchDetailsProcess`.`created_by`, `BatchDetailsProcess`.`updated_by`,
        `BatchDetailsProcess`.`created`, `BatchDetailsProcess`.`updated`,
        `BatchDetail`.`id`, `BatchDetail`.`batch_id`, `BatchDetail`.`po_transaction_id`,
        `BatchDetail`.`current_position`, `BatchDetail`.`out_date`,
        `BatchDetail`.`item_id`, `ProcessStep`.`id`, `ProcessStep`.`article_id`,
        `ProcessStep`.`production_step_id`, `ProcessStep`.`sequence`,
        `ProcessStep`.`rate_per`, `ProcessStep`.`amount_per`
    FROM  `star_impact`.`batch_details_processes` AS `BatchDetailsProcess`
    LEFT JOIN  `star_impact`.`batch_details` AS `BatchDetail`
           ON (`BatchDetailsProcess`.`batch_detail_id` = `BatchDetail`.`id`)
    LEFT JOIN  `star_impact`.`process_steps` AS `ProcessStep`
           ON (`BatchDetailsProcess`.`process_step_id` = `ProcessStep`.`id`)
    LEFT JOIN  `star_impact`.`batches` AS `Batch`
           ON (`Batch`.`id` = `BatchDetail`.`batch_id`)
    LEFT JOIN  `star_impact`.`article_ratios` AS `ArticleRatio`
           ON (`ArticleRatio`.`article_id` = `Batch`.`article_id`
              AND  `ArticleRatio`.`item_id` = `BatchDetail`.`item_id`
                          )
    WHERE  1 = 1

我想根据匹配的article_id＆amp;选择文章比率ITEM_ID。但结果并没有返回ArticleRatio，只返回BatchDetailProcess，BatchDetail和ProcessStep。

Answer 1

结果不会返回ArticleRatio

联接不是联想。

CakePHP的ORM不会发出SELECT *个查询，因此总是从问题中指定字段：

SELECT 
    ... <- No ArticleRatio here 
FROM 
    `star_impact`.`batch_details_processes` AS `BatchDetailsProcess` 
...
WHERE 
    1 = 1

如果select中没有提及，则联接表中不会返回任何字段，并且没有来自这些表的CakePHP数据。

或者：

指定查询中的字段

不要让CakePHP决定返回哪些字段，而是指定它们：

$conditions['fields'] = '*';
$bdp = $this->BatchDetailsProcess->find('all',$conditions);

SELECT 
    * <- Lazy, all fields. Or be more specific with 'fields'
FROM 
    `star_impact`.`batch_details_processes` AS `BatchDetailsProcess` 
...
WHERE 
    1 = 1

请注意，要查找的第二个参数是parameters而不是条件。

OR：

使用关联。

使用临时associations：

而不是加入

$this->BatchDetailsProcess->bindModel('hasOne', [
    'Batch' =>  [
        'conditions' => [
            'Batch.id = BatchDetail.batch_id'
        ]
    ],
    'ArticleRatio' => [
        'conditions' => [
            'ArticleRatio.article_id = Batch.article_id',
            'ArticleRatio.item_id = BatchDetail.item_id'
        ]
    ]
]);
$this->BatchDetailsProcess->find();

这将创建一个左连接，并添加填充响应中的字段/实体;调整传递给关联定义的参数（并使用containable）以适应。

加入表CakePHP

1 个答案:

联接不是联想。

指定查询中的字段

使用关联。