Question

我有一个有关联的模型。根表是Master_student。其他所有东西都有master_student_ssn的外键

<?php

class MasterStudent extends AppModel {

    var $name = 'MasterStudent';
    var $primaryKey = 'ssn';
    var $displayField = 'SSN';
    var $useTable = 'MASTER_STUDENTS';
    var $order = array("ssn" => "asc");




    var $hasMany = array(
        'MasterEmail' => array(
            'className' => 'MasterEmail',
            'foreignKey' => 'master_student_ssn',
            'conditions' => '',
            'order' => 'source',
            'limit' => '',
            'dependent' => true
        ),
        'MasterAddress' => array(
            'className' => 'MasterAddress',
            'foreignKey' => 'master_student_ssn',
            'conditions' => '',
            'order' => 'source',
            'limit' => '',
            'dependent' => true
        ),
        'MasterPhone' => array(
            'className' => 'MasterPhone',
            'foreignKey' => 'master_student_ssn',
            'conditions' => '',
            'order' => 'source',
            'limit' => '',
            'dependent' => true
        ),
        'MasterStudentName' => array(
            'className' => 'MasterStudentName',
            'foreignKey' => 'master_student_ssn',
            'conditions' => '',
            'order' => 'Effective_Date desc,source',
            'limit' => '',
            'dependent' => true
        )
    );

}

?>


 [MASTER_STUDENTS](
    [SSN] [int] NOT NULL,
    [date_student_added] [datetime] NULL,
 CONSTRAINT [PK_MASTER_STUDENT] PRIMARY KEY CLUSTERED 
(
    [SSN] ASC
)WITH (IGNORE_DUP_KEY = OFF) ON [PRIMARY]
) ON [PRIMARY]


[MASTER_ADDRESSES](
    [id] [int] IDENTITY(1,1) NOT NULL,
    [master_student_ssn] [int] NOT NULL,
    [address1] [varchar](50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
    [city] [varchar](50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
    [state] [varchar](50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
    [zip] [varchar](50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
 CONSTRAINT [PK_master_addresses] PRIMARY KEY CLUSTERED 
(
    [id] ASC
)WITH (IGNORE_DUP_KEY = OFF) ON [PRIMARY]
) ON [PRIMARY]

[MASTER_STUDENT_NAMES](
    [ID] [int] IDENTITY(1,1) NOT NULL,
    [master_student_ssn] [int] NOT NULL,
    [First_Name] [varchar](50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
    [Middle_Name] [varchar](50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
    [Last_Name] [varchar](50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
 CONSTRAINT [PK_MASTER_STUDENTS_NAMES] PRIMARY KEY CLUSTERED 
(
    [ID] ASC
)WITH (IGNORE_DUP_KEY = OFF) ON [PRIMARY]
) ON [PRIMARY]

我如何使用cake的find方法，以便我可以列出所有地址，电话，通过某人搜索而向某人发送的名字

1）姓氏 2）电话号码

即。我希望所有与模型相关的数据都通过cake在这些表上进行连接。

MasterStudent模型中的代码是

 $opts = array(
            'conditions' => array(
                'MasterStudentName.last_name LIKE ' => $searchvalue . '%'
            )
        );
        $this->MasterStudent->recursive = 1;
        $data = $this->MasterStudent->find('all', $opts);

使用JohnP方法生成的查询是

SELECT [MasterStudent]。[SSN] AS [MasterStudent__0]，CONVERT（VARCHAR（20），[MasterStudent]。[date_student_added]，20）AS [MasterStudent_ 1]，[MasterStudent]。[ssn] AS [MasterStudent _2]，[MasterStudent]。[ssn] AS [MasterStudent_ 8]，[MasterStudent]。[ssn] AS [MasterStudent _19]，[MasterStudent]。[ssn] AS [MasterStudent_ 26]，[MasterStudent]。[ssn] AS [MasterStudent _36] FROM [MASTER_STUDENTS] AS [MasterStudent] WHERE [MasterStudentName]。[Last_name] ='Smith'

Answer 1

组织数据的一种奇怪的方法，但是应该这样做。

$opts = array(
  'conditions' => array(
     'MasterStudentName.last_name' => 'something', //assuming last name is stored in MasterStudentName
     'MasterPhone.phone' => '23525222'
  )
);
$this->MasterStudent->recursive = 1;
$data = $this->MasterStudent->find('all', $opts);

递归设置为1，因此它将拉出所有关联。

cakephp - 加入表格

1 个答案: