Question

我有一个customer_orders表，如下所示，我想检索以相同顺序购买商品'x','y','z'的所有客户。只是想知道如何为这个问题实现解决方案。

输入数据： -

CREATE TABLE customer_orders
(
  customer_id INTEGER,
  order_id INTEGER,
  item_id INTEGER,
  ORDER_QTY INTEGER,
  PRICE INTEGER,
  ORDER_DATE DATE
 ); 

 INSERT INTO customer_orders VALUES(101,901,1,50,10,'2015-07-15'); 
 INSERT INTO customer_orders VALUES(101,901,2,20,50,'2015-07-15');
 INSERT INTO customer_orders VALUES(101,901,3,40,30,'2015-07-15'); 
 INSERT INTO customer_orders VALUES(102,902,2,30,15,'2015-04-16');
 INSERT INTO customer_orders VALUES(102,902,3,20,20,'2015-04-16');
 INSERT INTO customer_orders VALUES(103,903,1,50,10,'2014-05-17'); 
 INSERT INTO customer_orders VALUES(102,904,3,100,20,'2014-08-18'); 
 INSERT INTO customer_orders VALUES(101,905,2,200,15,'2014-09-19'); 
 INSERT INTO customer_orders VALUES(104,906,3,70,20,'2015-10-18'); 
 INSERT INTO customer_orders VALUES(104,906,2,30,15,'2015-10-18'); 
 INSERT INTO customer_orders VALUES(104,906,1,40,10,'2015-10-18'); 
 INSERT INTO customer_orders VALUES(105,907,2,80,15,'2014-03-29'); 
 INSERT INTO customer_orders VALUES(104,908,2,90,15,'2014-05-19');

输出： -

101
104

Assumption :- Item x --> 1, Item y ---> 2, Item z --> 3

Answer 1

您的解决方案实际上并未解决问题。您需要按订单对结果进行分组，以免混合不同订单中的订购商品，然后检索独特的客户：

SELECT DISTINCT 
         customer_id
FROM     customer_orders
WHERE    item_id BETWEEN 1 AND 3
GROUP BY customer_id, order_id
HAVING   COUNT( DISTINCT item_id ) = 3

例如，如果您从用户(1,2,3)的一个订单中删除列表101中的一个项目（例如：下方），那么在您的解决方案中，它仍然可以使用户101符合条件在输出中，因为他以不同的顺序订购了项目2。这种行为会使您的方法失去资格。

-- INSERT INTO customer_orders VALUES(101,901,2,20,50,'2015-07-15');

请参阅修改后的SQL Fiddle以查看我提到的问题。

获取在同一订单中购买三个指定商品的所有客户

1 个答案: