如何在sql中添加xml的所有子节点的属性

Question

我在变量@xml

中有一个类似下面的xml

<ContentTemplate>
  <Tab Title="Lesson">
    <Section Title="Lesson Opening" />
    <Section Title="Lesson/Activity" />
  </Tab>
  <Tab Title="Wrap Up and Assessment">
    <Section Title="Lesson Closing" />
    <Section Title="Tracking Progress/Daily Assessment" />
  </Tab>
  <Tab Title="Differentiated Instruction">
    <Section Title="Strategies - Keyword" />
    <Section Title="Strategies – Text" />
    <Section Title="Resources" />
    <Section Title="Acceleration/Enrichment" />
  </Tab>
  <Tab Title="District Resources">
    <Section Title="Related Content Items" />
    <Section Title="Other" />
  </Tab>
</ContentTemplate>

我想在上面的xml中为所有标签节点插入一个属性。     输出应如下所示：

<ContentTemplate>
      <Tab Title="Lesson" PortletName="CommunitiesViewer">
        <Section Title="Lesson Opening" />
        <Section Title="Lesson/Activity" />
      </Tab>
      <Tab Title="Wrap Up and Assessment" PortletName="CommunitiesViewer">
        <Section Title="Lesson Closing" />
        <Section Title="Tracking Progress/Daily Assessment" />
      </Tab>
      <Tab Title="Differentiated Instruction" PortletName="CommunitiesViewer">
        <Section Title="Strategies - Keyword" />
        <Section Title="Strategies – Text" />
        <Section Title="Resources" />
        <Section Title="Acceleration/Enrichment" />
      </Tab>
      <Tab Title="District Resources" PortletName="CommunitiesViewer">
        <Section Title="Related Content Items" />
        <Section Title="Other" />
      </Tab>
    </ContentTemplate>

我尝试了以下代码来获取上面的xml

set @xml.modify( 'insert attribute PortletName {sql:variable("@PortletName")} into (ContentTemplate/Tab)[1]')

它只是更新第一个子节点。

如何更新xml的所有子节点..

提前致谢

Answer 1

您在变量中的XML

DECLARE @xml XML=
N'<ContentTemplate>
  <Tab Title="Lesson">
    <Section Title="Lesson Opening" />
    <Section Title="Lesson/Activity" />
  </Tab>
  <Tab Title="Wrap Up and Assessment">
    <Section Title="Lesson Closing" />
    <Section Title="Tracking Progress/Daily Assessment" />
  </Tab>
  <Tab Title="Differentiated Instruction">
    <Section Title="Strategies - Keyword" />
    <Section Title="Strategies – Text" />
    <Section Title="Resources" />
    <Section Title="Acceleration/Enrichment" />
  </Tab>
  <Tab Title="District Resources">
    <Section Title="Related Content Items" />
    <Section Title="Other" />
  </Tab>
</ContentTemplate>';

1）FLWOR

.modify() - 语句允许您更改XML中的一个体面点，但您需要多次调用才能更改许多地方。 FLWOR允许您自行重新构建XML：

SET @xml=@xml.query(
'<ContentTemplate>
{
for $t in /ContentTemplate/Tab
   return 
   <Tab Title="{$t/@Title}" PortletName="CommunitiesViewer">
   {$t/*}
   </Tab>
}
</ContentTemplate>');

SELECT @xml

2）用SELECT ... FOR XML PATH()

重建

您可以通过这种方法达到相同的目标：重新构建XML，但这次它被粉碎并用作新的SELECT ... FOR XML PATH

SELECT tb.value('@Title','nvarchar(max)') AS [@Title]
      ,'CommunitiesViewer' AS [@PortletName]
      ,tb.query('*')
FROM @xml.nodes('/ContentTemplate/Tab') AS A(tb)
FOR XML PATH('Tab'),ROOT('ContentTemplate')