c＃循环列表随机数

Question

我有随机数生成器

 Random random = new Random();
    int x = random.Next(25);

和

List<int> mylist = new List<int>() {1,2,3,4,5,6,7}

那么如何在列表中循环，如果列表中有随机数，则将该数字放入文本框或标签中？

Answer 1

//Loop through each int in the list
foreach (int i in myList)
{
    //If the current int (i) equals the random (x)...
    if (i == x)
    {
        //Set it as the TextBox text (substitute out "someTextBox" for your TextBox or Label
        someTextBox.Text = i.ToString();
    }
}