Question

如果我想让用户输入一个字符串列表，我怎么能检查这些字符串是否与已定义的列表匹配？这是我试过的：

Cake = ["Flour", "Eggs", "Milk"]
Burger = ["Beef", "Buns", "Lettuce", "Cheese"]
Hot_Dog = ["Sausage", "Buns", "Ketchup", "Mustard"]
my_list = [Cake, Burger, Hot_Dog]
ingredients = input("I have: ")
if (ingredients == Hot_Dog or Burger or Cake):
    print(my_list)
else:
    print("Nothing here")

我知道这并不是我想要的。我的目的是让它从用户给出的成分中返回你可以制作的东西。所以，如果我输入＆＃34;面粉＆＃34; ＆＃34;鸡蛋＆＃34; ＆＆＃34; Milk＆＃34;，它会打印出＃34; Cake＆＃34;

Answer 1

如果您需要匹配成分然后打印出可以用它们制作的东西，请考虑使用词典作为主要数据结构。这使得成分列表与实际名称之间的对应关系非常容易使用：

 Context ctx = new InitialContext();
 DataSource ds = (DataSource)ctx.lookup("java:comp/env/jdbc/xxx");
 Connection conn = ds.getConnection();

如果某些成分匹配，这些将使打印

my_recipes = {
    'Cake':["Flour", "Eggs", "Milk"],
    'Burger':["Beef", "Buns", "Lettuce", "Cheese"],
    'Hot_Dog' : ["Sausage", "Buns", "Ketchup", "Mustard"],
}

变得更容易。

然后你可以采取一些'Cake'和input（默认的空白字符）：

split

并浏览字典ingredients = input("I have: ").split()中的食谱以匹配它们：

my_recipes

Answer 2

由于您只关心成分，而不关心它们的顺序，因此请使用集合和设置操作：

func GetLetterGoodness() []float32 {
    return [...]float32 { .0817,.0149,.0278,.0425,.1270,.0223 }
}

顺便说一下，Cake = set(["Flour", "Eggs", "Milk"]) Burger = set(["Beef", "Buns", "Lettuce", "Cheese"]) Hot_Dog = set(["Sausage", "Buns", "Ketchup", "Mustard"]) my_list = [Cake, Burger, Hot_Dog] ingredients = set(input("I have: ").split()) for food in my_list: if not(food - ingredients): print(food)是一组缺失的成分。

Answer 3

以下是解决此问题的简单示例：

cake_ingredients = ["Flour", "Eggs", "Milk"]
burguer_ingredients = ["Beef", "Buns", "Lettuce", "Cheese"]
hot_dog_ingredients = ["Sausage", "Buns", "Ketchup", "Mustard"]

my_list = {
    'cake': cake_ingredients,
    'burguer': burguer_ingredients,
    'hot_dog': hot_dog_ingredients
}

ingredients = "FlOur    EGGs   MiLk"

for k, v in my_list.items():
    v = set([ing.lower() for ing in v])
    remaining_ingredients = (
        v - set([ing.lower() for ing in ingredients.split()]))
    if len(remaining_ingredients) == 0:
        print("You got enough ingredients to make a {0}".format(k))
    else:
        print("You'd still need {0} to make a {1}".format(
            ','.join(remaining_ingredients), k
        ))

给定一个字符串列表，如何检查这些字符串是否在列表中？

3 个答案: