Question

我有以下查询：

SELECT 
    A.POSTCARD_ID, A.STAMP_ID, B.END_DT
FROM
    PST_VS_STAMP A
JOIN 
    STAMP B ON A.POSTCARD_ID = B.POSTCARD_ID
WHERE 
    B.ACCOUNT LIKE 'AA%'
    AND B.END_DT = '9999-12-31'
GROUP BY 
    A.POSTCARD_ID, A.STAMP_ID, B.END_DT
HAVING 
    COUNT(A.POSTCARD_ID) < 2

但我得到了错误的结果。

我只想要HAVING < 2表中有1条记录（PST_VS_STAMP）的明信片ID。我该如何查询？

Answer 1

在子查询中进行聚合，仅在您想要一行的表上进行。因为有一行，所以您可以使用聚合函数来提取任何列的值（对于一行min(col)是列的值）：

select s.postcard_id, vs.stamp_id, s.end_dt
from stamp s join
     (select vs.postcard_id, min(stamp_id) as stamp_id
      from pst_vs_stamp vs
      group by vs.postcard_id
      having count(*) = 1
     ) s
     on vs.POSTCARD_ID = s.POSTCARD_ID
where s.ACCOUNT like 'AA%' and s.END_DT = '9999-12-31';

选择连接表中唯一存在1的记录

1 个答案: