我必须过滤一个对象数组,以获得基于另一个数组的特定值,并且也是
数据
var value:any[]
var inventory = [
{id: 1, quantity: 2, GroupId: 1},
{id: 2, quantity: 0, GroupId: 2},
{id: 1, quantity: 2, GroupId: 1}
];
//data from db
value = [1,2]
我的代码
var data = this.inventory .filter(x => x.GroupId == this.value );
无法获取已过滤的数据,但返回空数组。提前致谢
答案 0 :(得分:5)
在您的代码中,您将GroupId
与数组进行比较。您应该检查数组是否包含GroupId
。
以下是如何操作:
var data = this.inventory.filter(x => value.includes(x.GroupId));
为了获得更好的支持,您可以将Array.prototype.includes替换为Array.prototype.indexOf:
var data = this.inventory.filter(x => value.indexOf(x.GroupId) !== -1);
答案 1 :(得分:3)
如果你想通过id字段区分这里是一个解决方案:
var inventory = [
{id: 1, quantity: 2, GroupId: 1},
{id: 2, quantity: 0, GroupId: 2},
{id: 1, quantity: 2, GroupId: 1}
];
var value = [1,2]
var data = inventory.filter(x => value.indexOf(x.GroupId)>-1).filter((elem1, pos, arr) => arr.findIndex((elem2)=>elem2.id === elem1.id) === pos);
console.log(data);
JSFiddle示例:https://jsfiddle.net/7xnybhLv/1/
答案 2 :(得分:1)
您应该使用包含
console.log([
{id: 1, quantity: 2, GroupId: 1},
{id: 2, quantity: 0, GroupId: 2},
{id: 3, quantity: 2, GroupId: 1}
].filter(x => [1,2].includes(x.id)));

答案 3 :(得分:0)
您可以直接使用变量并使用Array#includes
。
var inventory = [{ id: 1, quantity: 2, GroupId: 1 }, { id: 2, quantity: 0, GroupId: 2 }, { id: 3, quantity: 2, GroupId: 1 }],
value = [1, 2],
data = inventory.filter(({ GroupId }) => value.includes(GroupId));
console.log(data);
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