我正在尝试通过递归在汇编中实现斐波那契数列。这是我第一次尝试在x86 Assembly中实现递归。
代码可以正常编译,但是输出错误。输出1为1,输出2为0,输出3为1,输出4为2,输出5为3。
仅当您插入5时,它的输出才正确。
算法有问题吗?
.DATA
n1 DWORD ?
prompt1 BYTE "Please enter the first value", 0
prompt3 BYTE "No negative numbers!",0
string BYTE 40 DUP (?)
resultLbl BYTE "The Fib is: ", 0
fib BYTE 40 DUP (?), 0
.CODE
_MainProc PROC
input prompt1, string, 40
atod string
test eax, eax
js signed
mov n1, eax
jmp procName
signed:
output prompt3, string
jmp end1
procName:
mov eax, n1
push n1
call fib1
add esp,4
dtoa fib, eax
output resultLbl, fib
end1:
mov eax, 0
ret
_MainProc ENDP
Fib1 proc
PUSH EBP ; save previous frame pointer
MOV EBP, ESP ; set current frame pointer
MOV EAX, [EBP+8] ; get argument N
CMP EAX, 1 ; N<=1?
JA Recurse ; no, compute it recursively
MOV ECX, 1 ; yes, Fib(1)--> 1
JMP exit
Recurse:
DEC EAX ; = N-1
MOV EDX, EAX ; = N-1
PUSH EDX ; save N-1
PUSH EAX ; set argument = N-1
CALL Fib1 ; compute Fib(N-1) to ECX
POP EAX ; pop N-1
DEC EAX ; = N-2
PUSH ECX ; save Fib(N-1)
PUSH EAX ; set argument = N-2
CALL Fib1 ; compute Fib(N-2) to ECX
POP EAX ; = Fib(N-1)
ADD ECX, EAX ; = Fib(N-1)+FIB(N-2)
exit:
MOV ESP,EBP ; reset stack to value at function entry
POP EBP ; restore caller's frame pointer
RET
Fib1 endp
END