Question

我需要创建一个报告，我只需要通过月份（二月）和一年（2011年），并希望sum(total)输出所需的输出...我不知道如何计算总周数< / p>

Week-1......Week-2......Week-3......Week-4....Total 
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Answer 1

工作示例

示例表，仅包含2列thedate datetime, amount numeric

select cast(datediff(d, number%1000, getdate()) as datetime) as thedate, number as amount
into testtable
from master..spt_values

将月份和年份作为参数的查询

declare @month int, @year int
select @month = 2, @year = 2011

select *
from
(
select
    amount,
    'Week-' + right(dense_rank() over (order by datepart(wk, thedate)),1) week_in_month
from testtable
where thedate >= cast(@year*10000+@month*100+1 as char(8))
  and thedate <  dateadd(m,1,cast(@year*10000+@month*100+1 as char(8)))
) P
pivot (sum(amount) for week_in_month in ([Week-1],[Week-2],[Week-3],[Week-4],[Week-5])) V

注意：

cast(@year*10000+@month*100+1 as char(8))：每月的第一天
dateadd(m,1,..)：

SQL Server查询以计算给定月份名称中的总周数

1 个答案: