Spring.Net程序化与XML配置

Question

如果我用XML定义对象并调用var xmlApplicationContext = new XmlApplicationContext()，则会安排作业并触发。我想要完成的是通过代码执行此操作，因为属性将是动态的，下面的方法片段编译并运行但作业未安排。这可能吗？

// SpringJob.xml

<objects xmlns="http://www.springframework.net" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
        <object name="emailNotification" type="Spring.Scheduling.Quartz.JobDetailObject, Spring.Scheduling.Quartz">
            <property name="JobType" value="Project.Agent.Jobs.EmailNotification, Project.Agent" />
        </object>
        <object id="simpleTrigger" type="Spring.Scheduling.Quartz.SimpleTriggerObject, Spring.Scheduling.Quartz">
            <property name="jobDetail" ref="emailNotification" />
            <property name="startDelay" value="1s" />
            <property name="repeatInterval" value="1s" />
            <property name="repeatCount" value="0" />
        </object>
        <object type="Spring.Scheduling.Quartz.SchedulerFactoryObject, Spring.Scheduling.Quartz">
            <property name="triggers">
                <list>
                    <ref object="simpleTrigger" />
                </list>
            </property>
        </object>
</objects>

//方法

 var jobDetailObject = new JobDetailObject
                                              {
                                                  JobType = new EmailNotification().GetType()
                                              };

    var simpleTrigger = new SimpleTriggerObject
                            {
                                JobDetail = jobDetailObject,
                                StartDelay = new TimeSpan(0, 0, 0, 1),
                                RepeatInterval = new TimeSpan(0, 0, 0, 1),
                                RepeatCount = 0
                            };

    var scheduleTrigger = new SchedulerFactoryObject();
    var triggers = new Trigger[1];
    triggers[0] = simpleTrigger;
    scheduleTrigger.Triggers = triggers;
    scheduleTrigger.Start();

Answer 1

决定放弃Quartz.Net的Spring.Net框架实现，而不是直接使用Quartz.Net。