Question

我要在内核中做什么：

while (TRUE)
{
    //DbgPrintEx(0, 0, "First loop is running \n");
    ReadSharedMemory();


        if (!(PCHAR)SharedSection == NULL && strcmp((PCHAR)SharedSection, "Read") == 0)
        {
            DbgPrintEx(0, 0, "Read looping \n");

            RtlZeroMemory(SharedSection, sizeof(SharedSection));
            break;
        }
        else if (!(PCHAR)SharedSection == NULL && strcmp((PCHAR)SharedSection, "Write") == 0)
        {
            DbgPrintEx(0, 0, "Write looping \n");
            RtlZeroMemory(SharedSection, sizeof(SharedSection));
            break;
        }
    LARGE_INTEGER Timeout;
    Timeout.QuadPart = RELATIVE(SECONDS(1));
    KeDelayExecutionThread(KernelMode, FALSE, &Timeout);
}

并在用户模式下：

    auto pBufW = (char*)MapViewOfFile(hMapFileW, FILE_MAP_WRITE, 0, 0, 4096);


RtlCopyMemory(pBufW, "Read", 4);

printf("message has been sent to kernel! \n");


UnmapViewOfFile(pBufW);

Sleep(10);

auto pBfW = (char*)MapViewOfFile(hMapFileW, FILE_MAP_WRITE, 0, 0, 4096);


RtlCopyMemory(pBfW, "Write", 5);

printf("message has been sent to kernel! \n");


UnmapViewOfFile(pBfW);

我无法弄清楚为什么我叫Read and Write。只写执行我已经尝试了多次，并且它总是这样做+我试图添加一个sleep（1）;在我的用户模式下（认为它执行得非常快）。

基本上，我只需要它们正常执行，就像应该先执行Read然后执行Write一样。

Answer 1

有人帮了我，这就是我所做的

  while ( memcmp( pBufW, "Read", 4) == 0 )
    {
           Sleep(1);
    }
UnmapViewOfFile(pBufW);

简单检查，现在可以正常使用：D

共享内存执行得这么快？

1 个答案: