多个InStr（）函数语法问题

Question

我知道有比拥有多个InStr（）函数更好的方法，但是我对VBA不够满意，无法知道如何实现它们。因此，与此同时，我认为拥有多个InStr（）可以工作，但是我似乎无法理清所有InStr（）的语法问题。请帮忙！

'Search code
LastRow = Alpha.Cells.Find(What:="*", After:=[A1], SearchOrder:=xlByRows,_
SearchDirection:=xlPrevious).Row

'Loop search code
For i = 2 To LastRow

   'Check if columns do not match
    If Alpha.Range("G" & i) <> Alpha.Range("H" & i) Then

   'Pull out mismatches if contain specific strings
    Select Case True
        'Search for specific strings
         Case ((InStr(1, Alpha.Range("H" & i), "E08.3") > 0) Or _
            (InStr(1, Alpha.Range("H" & i), "E08.4") > 0) Or _
            (InStr(1, Alpha.Range("H" & i), "E08.5") > 0) Or _
            (InStr(1, Alpha.Range("H" & i), "E08.6") > 0) Or _
            (InStr(1, Alpha.Range("H" & i), "E08.8") > 0) Or _
            (InStr(1, Alpha.Range("H" & i), "E08.9") > 0)) Or _
            (InStr(1, Alpha.Range("H" & i), "E09") > 0) Or _
            (InStr(1, Alpha.Range("H" & i), "E10") > 0) Or _
            (InStr(1, Alpha.Range("H" & i), "E11") > 0) Or _
            (InStr(1, Alpha.Range("H" & i), "E13.0") > 0) Or _
            (InStr(1, Alpha.Range("H" & i), "E13.1") > 0) Or _
            (InStr(1, Alpha.Range("H" & i), "E13.2") > 0) Or _
            (InStr(1, Alpha.Range("H" & i), "E13.3") > 0)) And _
         ((InStr(1, Alpha.Range("K" & i), "J0718") > 0) Or _
            (InStr(1, Alpha.Range("K" & i), "J2778") > 0) Or _
            (InStr(1, Alpha.Range("K" & i), "J9035") > 0) Or _
            (InStr(1, Alpha.Range("K" & i), "J7312") > 0) Or _
            (InStr(1, Alpha.Range("K" & i), "C9257") > 0))

            'look for UniqueID(colA) in TrackSheet to avoid duplicate copy
             DuplicateCheck = Application.Match(Alpha.Range("A" & i).Value,_ 
             TrackSheet.Columns(1), 0)
             If IsError(DuplicateCheck) Then
                   'If no match on UniqueID, copy values
                    TrackSheet.Cells(Rows.Count, 1).End(xlUp)._
                    Offset(1,0).EntireRow.Value = Alpha.Rows(i).Value                
            End If

     End Select
     End If

Next i