Question

我想像这样将数组转换为字符串

$stations_id = Station::pluck('id'); // Output [1,2,3,4]
$schedules = [];
foreach ($stations_id as $station_id) {
     $schedules[] = Schedule::select('id')
                    ->where('station_id', $station_id)
                    ->latest()
                    ->first();                
}

// second loop here

$queues = [];
foreach ($schedules as $schedule) {       
    $queues[] = Queue::withTrashed()
             ->latest()
             ->where('schedule_id', $schedule->getKey())->first();               
}

// do something with queues

到

let myArray:[Any] = ["element 1", "element 2", ["element 3.1", "element 3.2"], "element 4"]

我已经尝试过了

let convertedString = "[\"element 1\",\"element 2\",\"[\\\"element 3.1\\\",\\\"element 3.2\\\"]\",\"element 4\"]"

但是我得到这个结果

do {
    let jsonData: Data = try JSONSerialization.data(withJSONObject: myArray, options: [])
    if  let jsonString = NSString(data: jsonData, encoding: String.Encoding.utf8.rawValue) {
        print(jsonString)
    }

} catch let error as NSError {
    print("Array convertIntoJSON - \(error.description)")
}

我已经使用JSONArray在Java中完成了此操作。我只是调用toString方法在Java中执行此操作。我需要像上面给出的示例一样将第三个元素作为字符串。

Answer 1

这应该做：

"\(myArray.map { "\($0)" })"

如何快速将数组转换为字符串？

1 个答案: