Question

我遇到了Dropbox API的问题。

当我尝试获取文件夹的元数据时，我得到如下数据输出：

{"hash":"10f86b5b7c9c9276501f67a71ecd41c9","thumb_exists":false,"bytes":0,"path":"\/","is_dir":true,"size":"0 bytes","root":"app_folder","contents":[{"revision":7,"rev":"7069e0896","thumb_exists":true,"bytes":19749,"modified":"Tue, 20 Mar 2012 05:06:43 +0000","client_mtime":"Mon, 26 Sep 2011 11:50:43 +0000","path":"\/1_sml.jpg","is_dir":false,"icon":"page_white_picture","root":"dropbox","mime_type":"image\/jpeg","size":"19.3 KB"},{"revision":6,"rev":"6069e0896","thumb_exists":true,"bytes":15797,"modified":"Tue, 20 Mar 2012 05:06:43 +0000","client_mtime":"Mon, 26 Sep 2011 11:51:09 +0000","path":"\/2_sml.jpg","is_dir":false,"icon":"page_white_picture","root":"dropbox","mime_type":"image\/jpeg","size":"15.4 KB"},{"revision":5,"rev":"5069e0896","thumb_exists":true,"bytes":13349,"modified":"Tue, 20 Mar 2012 05:06:43 +0000","client_mtime":"Mon, 26 Sep 2011 11:51:26 +0000","path":"\/3_sml.jpg","is_dir":false,"icon":"page_white_picture","root":"dropbox","mime_type":"image\/jpeg","size":"13 KB"},{"revision":4,"rev":"4069e0896","thumb_exists":true,"bytes":8838,"modified":"Tue, 20 Mar 2012 05:06:43 +0000","client_mtime":"Mon, 26 Sep 2011 11:51:46 +0000","path":"\/4_sml.jpg","is_dir":false,"icon":"page_white_picture","root":"dropbox","mime_type":"image\/jpeg","size":"8.6 KB"},{"revision":3,"rev":"3069e0896","thumb_exists":true,"bytes":99646,"modified":"Tue, 20 Mar 2012 04:57:58 +0000","client_mtime":"Tue, 20 Sep 2011 14:14:26 +0000","path":"\/bg.jpg","is_dir":false,"icon":"page_white_picture","root":"dropbox","mime_type":"image\/jpeg","size":"97.3 KB"}],"icon":"folder"}

我的问题是我想获得每个图像/文件名的输出..但我可以找到正确的方法来做到这一点..我通过我可以这样做：

$info = json_encode($dropbox->getMetaData(''));
foreach($info->contents->path as $file){
    echo $file;
}

但是我收到了这个错误：

Warning: Invalid argument supplied for foreach() in /home/djrasmusp/rasmusp.com/db/index.php on line 16

但有没有人可以帮我解决问题？

Answer 1

尝试使用json_decode代替json_encode（并且可能使用第二个参数来生成关联数组而不是stdClass）。

Answer 2

我有同样的问题，这是我的解决方案：

$metaData = $dropbox->metaData($path);

foreach($metaData['body']->contents as $file){
    $f = str_replace("/", "", $file->path);
    echo "<li>$f</li>";
}

Answer 3

由我测试：）

require_once('bootstrap.php');
$metaData = $dropbox->metaData();
foreach($metaData['body']->contents as $file)
{ 
   echo "<pre>";
   echo $file->path; 
}

列出dropbox文件夹中的文件

3 个答案: