两条线的交叉点

Question

我试图找到Line2D个对象的点，或者只是在它的交叉处回答。我现在得到的就是定义的行和代码的这一部分：

class Linia {
    public java.awt.geom.Line2D.Double getLine() {
        return line;
    }
    public void setLine(java.awt.geom.Line2D.Double line) {
        this.line = line;
    }
    private java.awt.geom.Line2D.Double line;
}

public class Lines {

    public static java.awt.geom.Line2D.Double create(double x1, double y1,double x2, double y2) {
        java.awt.geom.Line2D.Double tmpL = new java.awt.geom.Line2D.Double();
        tmpL.x1 = x1;
        tmpL.y1 = y1;       
        tmpL.x2 = x2;
        tmpL.y2 = y2;
        return tmpL;    
    }
    public int getIle() { 
        return ile;
    }
    public void setIle(int k) {
        this.ile=ile;
    }
    private int ile;

    public static void main(String[] args) {
        int j, a = 0, z = 0, i, v = 0;

        Scanner f = new Scanner(System.in);
        j = f.nextInt();

        double pktx[] = new double[j];
        double pkty[] = new double[j];
        Lines ile1 = new Lines();
        ile1.setIle(Integer.valueOf(j));
        for (i = 0; i < j; i++) {
            Scanner h = new Scanner(System.in);
            pktx[i] = h.nextInt();
            Scanner o = new Scanner(System.in);
            pkty[i] = o.nextInt();
        }
        for (i = j - 1; i > 0; i--) {
            a=a+i;
        }
        Linia[] line = new Linia[a];
        for (v = 0; v < a; v++) line[v]=new Linia();
        v=0;
        for (z = 0; z < j; z++) {
            double d=pktx[z];
            double y=pkty[z];
            for (i = z + 1; i < j; i++) {

                double u = pktx[i];
                double t = pkty[i];
                line[v].setLine(create(Double.valueOf(d), Double.valueOf(y), Double.valueOf(u), Double.valueOf(t)));
                System.out.println("Linia " + v + " " + line[v].getLine().getBounds());
                v++;
            }
        }
        CTriangle count=new CTriangle();
        count.linesIntersect(line[3], line[5]);
    }
}    

public class CTriangle {

    public static boolean linesIntersect(Linia l1, Linia l2)    {
        System.out.println("Crossing");
        return false;
    }
}

对于积分1,1 4,1 4,4 1,4，似乎没有Crossing，但确实如此。

我正在寻找显示üoint交点的方法，因为方法linesIntersection正在返回false或true。或者正确实施方法linesintersection。

Answer 1

有人告诉我，我可以在linesIntersection方法中使用get行。也许有问题？或者更好地使用连接到类line2d的任何其他mothode来找到交叉点。