Question

这是我的作业。我可以返回无效，但我不知道如何使用int以及如何检查出现问题并返回-1;

ADTSmatrix是：

航向

整数的稀疏矩阵（具有维行x cols）。

功能：

int SMTX_read (SMatrixType A)

::= read in a matrix from stdin and stores the matrix in A.
::= returns SMTX_ERROR if something went wrong
--------/* For this project, the input format will be
Line 1: two integers, rows & cols, dimension of the matrix Line 2 to rows+1: contains cols number of integers
Should take the input and convert to your proper ADT format */


int SMTX_print(SMatrixType A)

::= print the sparse matrix A in the following format
/* Line 1: print “Rows = ??, Cols = ??, # of non-zero entries = ??” Line 2 ~ ??: print “< Ri, Ci, entry-value>,” one 3-tuple per line */



int SMTX_add (SMatrixType A, B, C)

::= C <= A + B
::= returns SMTX_ERROR if something went wrong

int SMTX_subtract (SMatrixType A, B, C)

::= C <= A - B
::= returns SMTX_ERROR if something went wrong

int SMTX_transpose (SMatrixType A, B) ::= B <= AT

::= returns SMTX_ERROR if something went wrong

int SMTX_multiply (SMatrixType A, B, C)



 ::= C <= A x B
    ::= returns SMTX_ERROR if something went wrong /* please use the quick 

algorithm given in lecture */

数据输入：

define SMTX_ERROR -1
define MAX_SMTX_SIZE 100
typedef struct SMatrix {
. ..
} SMatrixType

Answer 1

错误处理旨在通过返回值执行。当期望完全没有错误时，Void可以是例如打印功能。读取功能和其他操作应检查输入：e。 G。矩阵具有相应的维度，或者可能出现其他问题，结果与期望不符。

int SMTX_read (SMatrixType A)
{
    int err = 0;
    /* reading input */
    if( outcome != expected ) { err = SMTX_ERROR; }
    /* .. */
    return err;
}

或另一个例子：

int division( int dividend, int divisor, int * quotient_ptr )
{
    int err = -1;
    if( 0 != divisor ) { err = 0; *quotient_ptr = dividend / divisor; }
    return err;
}

稀疏矩阵函数

1 个答案: